jQuery动画摇动悬停

Question

我试图在没有使用jQuery UI的情况下悬停元素并且遇到以下代码,但是我似乎无法弄清楚如何在悬停时触发,此代码具有随机效果并且每次我尝试时都会让我感到困惑弥漫它.我试图让他们一次动画一个,而不是完全

http://jsfiddle.net/g6AeL/

   $(function() {
      var interval = 10;
      var duration= 1000;
      var shake= 3;
      var vibrateIndex = 0;
      var selector = $('aside.featured a'); /* Your own container ID*/
        $(selector).click( /* The button ID */

        function(){ 

        vibrateIndex = setInterval(vibrate, interval);
        setTimeout(stopVibration, duration);

        });

        var vibrate = function(){
        $(selector).stop(true,false)
        .css({position: 'relative', 
        left: Math.round(Math.random() * shake) - ((shake + 1) / 2) +'px', 
        top: Math.round(Math.random() * shake) - ((shake + 1) / 2) +'px'
        });
        }

        var stopVibration = function() {
        clearInterval(vibrateIndex);
        $(selector).stop(true,false)
                .css({position: 'static', left: '0px', top: '0px'});
            };

        });

Answer 1

试试这种方式: -

$(function() {
  var interval = 10;
  var duration= 1000;
  var shake= 3;
  var vibrateIndex = 0;
  var selector = $('.box'); /* Your own container ID*/
    $(selector).hover( /* The button ID */
        function(){ 
        vibrateIndex = setInterval(vibrate, interval);    
        },
        function(){ 
            clearInterval(vibrateIndex);
            $(selector).stop(true,false)
                .css({position: 'static', left: '0px', top: '0px'});
        }
    );

    var vibrate = function(){
        $(selector).stop(true,false)
        .css({position: 'relative', 
        left: Math.round(Math.random() * shake) - ((shake + 1) / 2) +'px', 
        top: Math.round(Math.random() * shake) - ((shake + 1) / 2) +'px'
        });
    }
});

请参阅此演示