我想从我的应用程序向用户发送一封电子邮件,其中包含从视图中加载的电子邮件的内容 .这是我到目前为止尝试过的代码:
$toemail = "user@email.id";
$subject = "Mail Subject is here";
$mesg = $this->load->view('template/email');
$this->load->library('email');
$config['charset'] = 'utf-8';
$config['wordwrap'] = TRUE;
$config['mailtype'] = 'html';
$this->email->initialize($config);
$this->email->to($toemail);
$this->email->from($fromemail, "Title");
$this->email->subject($subject);
$this->email->message($mesg);
$mail = $this->email->send();
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Nir*_*jan 18
$this->load->library('email');
在控制器内 调用CI中的电子邮件才能工作.$fromemail
未初始化.工作守则:
$this->load->library('email');
$fromemail="ad@c.com";
$toemail = "user@email.id";
$subject = "Mail Subject is here";
$data=array();
// $mesg = $this->load->view('template/email',$data,true);
// or
$mesg = $this->load->view('template/email','',true);
$config=array(
'charset'=>'utf-8',
'wordwrap'=> TRUE,
'mailtype' => 'html'
);
$this->email->initialize($config);
$this->email->to($toemail);
$this->email->from($fromemail, "Title");
$this->email->subject($subject);
$this->email->message($mesg);
$mail = $this->email->send();
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编辑:
$mesg = $this->load->view('template/email',true);
应该是由lycanian指出的真实.通过将其设置为true,它不会将数据发送到输出流,但会以字符串形式返回.
编辑:
$this->load->view();
需要第二个参数与数据或空相似$mesg = $this->load->view(view,data,true);
,如果不是它不会工作
小智 8
这行$ mesg = $ this-> load-> view('template/email',true); 应该像这样
$ mesg = $ this-> load-> view('template/email','',true);
在值为true之前使用单引号,它将完美地工作