array_keys 在 php 中返回数组

use*_*o01 0 php arrays

我有这个功能

protected function insert($data){
        $data['datecreated'] = date('Y-m-d h:i:s');
        echo "array_keys(data) = ".$data['datecreated'];
        var_dump($data);
        echo array_keys($data);
        $sql = "INSERT INTO {$this->table_name} (".  array_keys($data).")"; 
        $sql.= " VALUES ('";
        $sql.=implode("','", $data);
        $sql.=")";
        $this->execute($sql);
        $this->last_id = mysql_insert_id();
    }
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当我阅读array_keys($data)它时,它返回“数组”而不是我这样称呼它的键,这$this->insert(array());是为什么?编辑:这是输出

array_keys(data) = 2012-05-18 04:44:46array(2) { [0]=> array(0) { } ["datecreated"]=> string(19) "2012-05-18 04:44:46" } Array
Notice: Array to string conversion in /Applications/MAMP/htdocs/Tamara/model/dbTable.php on line 105
INSERT INTO account (Array) VALUES ('Array','2012-05-18 04:44:46)You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''2012-05-18 04:44:46)' at line 1
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mpr*_*att 5

array_keys 返回一个包含所有键的数组。你也需要内爆

implode(',', array_keys($data));
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编辑:你可能想看看这部分

$sql.=implode("','", $data);
$sql.=")";
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你需要一个开始和尾随'