Mat*_*Mat 35 java spring jpa jpql spring-data
我有简单的Entitly类@EmbeddedId
(Integer
和String
单独的类中的字段).我使用Spring Data(org.springframework.data.jpa.repository.JpaRepository
)访问数据库(MySql),正常的Id查询工作正常,由Spring生成和我自己编写的.随着EmbeddedId
我没有管理,以创建正确的查询.我想要做的是选择所有的id(其中某个条件发生的embeddedId的一个字段)在这里你有一些代码示例,也许有人会知道如何解决它.
实体类:
@Entity
@Table(name="table_name")
public class EntityClass {
@EmbeddedId
private EmbeddedIdClass id;
private String someField;
//rest of implemetation
}
Run Code Online (Sandbox Code Playgroud)
EmbeddedId类:
@Embeddable
public class EmbeddedIdClass implements Serializable {
public EmbeddedIdClass(Long id, String language) {
super();
this.id = id;
this.language = language;
}
public UserAdTextId() {}
@Column(name="ad_id", nullable=false)
private Integer id;
@Column(name="language_code", nullable=false)
private String language;
//rest of implemetation
}
Run Code Online (Sandbox Code Playgroud)
和存储库:
@Transactional(readOnly=true)
public interface MyRepository extends JpaRepository<EntityClass, EmbeddedIdClass> {
@Query("select distinct ad_id from EntityClass where userId = :userId and (/*here the conditions*/)")
public Page<Integer> findUserAdsWithSearchString(@Param("userId") Integer userId, @Param("searchString") String searchString, Pageable page);
//rest of implemetation
}
Run Code Online (Sandbox Code Playgroud)
我没有找到任何文档如何创建支持@EmbeddedId的方法,我尝试了许多不同的方法名称,但我总是从方法解析器获得异常..
yle*_*lev 40
(作者:Yosi Lev)这可以通过以下方式完成:假设您的主要实体是:
@Entity
@Table(name="JRULES_FLOW")
public class JrulesFlow implements Serializable {
private static final long serialVersionUID = 1L;
@EmbeddedId
private JrulesFlowPK id;
@Column(name="NEXT_SEQ")
private int nextSeq;
@Column(name="REF_ID")
private String refId;
@Column(name="TASK_TYPE")
private String taskType;
@Column(name="VALUE_TO_FIND")
private String valueToFind;
}
Run Code Online (Sandbox Code Playgroud)
你的PK课程是:
@Embeddable
public class JrulesFlowPK implements Serializable {
//default serial version id, required for serializable classes.
private static final long serialVersionUID = 1L;
@Column(name="FLOW_ID")
private String flowId;
@Column(name="TASK_SEQ")
private long taskSeq;
}
Run Code Online (Sandbox Code Playgroud)
JPA存储库方法名称包含主类中的id字段的名称,后跟要在PK类中查询的属性:
public interface JrulesFlowRepository extends JpaRepository<JrulesFlow,
JrulesFlowPK> { // NOTE: put here both classes - also the pk class..
public List<JrulesFlow> findByIdFlowId(String flowId); // Id - is the
// @EmbeddedId in JrulesFlow. FlowId is an attribute
// within JrulesFlowPK
}
Run Code Online (Sandbox Code Playgroud)
Xav*_*ica 16
您的查询似乎正在使用列名称.它应包含属性名称,包括导入嵌入对象.这里还有一个相关的问题:如何用嵌入式id编写JPQL SELECT?
select distinct id.id from EntityClass where userId = :userId and (...)
Run Code Online (Sandbox Code Playgroud)
第一个id
引用(类型)属性id
,第二个引用属性.EntityClass
EmbeddedIdClass
id
EmbeddedIdClass
另外,请确保有userId
房产EntityClass
.