例如,我有两个数组:
var list1 = string[] {"1", "2", "3", "4", "5", "6"};
var list2 = string[] {"2", "3", "4"};
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我想做的是 -
list1
和list2
(例如,{ "2", "3", "4"})list1
和list2
(例如,{ "1", "5", "6"})所以我试过LINQ和 -
var listDiff = list1.Except(list2); //This gets the desire result for different items
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但,
var listCommon = list1.Intersect(list2); //This doesn't give me desire result. Comes out as {"1", "5", "6", "2", "3", "4"};
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有任何想法吗?
Guf*_*ffa 26
不知何故,你从其他地方得到了这个结果.(也许你正在写出listDIff
第一个内容,并认为它来自listCommon
.)该Intersect
方法确实为您提供了两个列表中存在的项目:
var list1 = new string[] {"1", "2", "3", "4", "5", "6"};
var list2 = new string[] {"2", "3", "4"};
var listCommon = list1.Intersect(list2);
foreach (string s in listCommon) Console.WriteLine(s);
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输出:
2
3
4
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