使用CodeIgniter验证后使用POST数据

Question

我有一个注册表单,我正在验证用户输入.这是我的控制器:

<?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');

class Register extends CI_Controller {

    public function index()
    {
        $this->load->model('Users_model');
        $this->load->helper('form');
        $this->load->library('form_validation');

        $data['page_title'] = 'Register';
        $this->load->view('header', $data);

        // Set form validation rules
        $this->form_validation->set_rules('username', 'Username', 'trim|required|min_length[5]|max_length[16]|xss_clean|callback_username_check');
        $this->form_validation->set_rules('email', 'Email', 'trim|required|min_length[5]|max_length[64]|valid_email|callback_email_check');
        $this->form_validation->set_rules('password', 'Password', 'required');
        $this->form_validation->set_error_delimiters('<span class="error">', '</span>');

        if ($this->form_validation->run() == FALSE)
        {
            $this->load->view('register', $data);
        }
        else
        {
            // Add the user to the database
            $this->Users_model->add_user();
            $this->load->view('register_success', $data);
        }

        $this->load->view('footer', $data);
    }

    /* Functions to check username and email */
}

/* End of file register.php */
/* Location: ./application/controllers/register.php */

问题出在这一行:$this->Users_model->add_user();.我想将用户名,电子邮件和密码传递给我的用户模型,以将用户添加到我的数据库中,但我不确定如何将POST数据传入该方法.一般情况下我使用$_POST['username']等,但笨已经运行的输入值(某些功能trim(),xss_clean等等).我怎样才能获得这些值并将它们传递给我的add_user()方法？

Answer 1

该CodeIgniter的输入类可以让你得到POST数据已经通过表单验证库过滤后.在您的控制器中,您将执行以下操作:

$username = $this->input->post('username');
$email = $this->input->post('email');
$password = $this->input->post('password');