我有这样的文件
EntityName Jaws
{
Animation WALK
{
NumberOfFrames 9
DirectionOfSprite L
DirectionGenerate LR
FPS 9
}
Animation IDLE
{
NumberOfFrames 6
DirectionOfSprite L
DirectionGenerate LR
FPS 9
}
.......
.......
}
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如何在此结构中解析此文件
struct AnimationData
{
string animationName;
int noOfFrames;
eAnimationDataDirection direction;
int FPS;
};
struct EntityAnimationData
{
string entityName;
vector<AnimationData> animationData;
string getSpriteResourceName(AnimationData animationData, int frameNumber);
};
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我想将这些数据存储到结构中.我该如何获得一个干净的解决方案?我已经阅读了文件的基本阅读材料.
这就是我尝试过的
EntityAnimationData parseAnimationData(const char* filename)
{
EntityAnimationData data;
ifstream file;
file.open(filename);
char output[128];
string op;
if (file.is_open())
{
while (!file.eof())
{
file >> output;
if(strcmp(parameter,AD_ENTITY_NAME.c_str())==0)
{
file >> output;
data.entityName = output;
cout<<data.entityName<<endl;
do
{
file >> output;
cout<<output<<endl;
}while(strcmp(output,"}")!=0);
}
}
}
file.close();
return data;
}
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