如何将两个位图合并到另一个位图

Hec*_*888 24 java android

我有两个图像,我想将一个位图图像精确地保存在另一个位置,在它存在的同一点我也使用手势移动图像.

public Bitmap combineImages(Bitmap ScaledBitmap, Bitmap bit) {

        int X = bit.getWidth();
        int Y = bit.getHeight();

        Scaled_X = ScaledBitmap.getWidth();
        scaled_Y = ScaledBitmap.getHeight();

        System.out.println("Combined Images");

        System.out.println("Bit :" + X + "/t" + Y);

        System.out.println("SCaled_Bitmap :" + Scaled_X + "\t" + scaled_Y);

        overlaybitmap = Bitmap.createBitmap(ScaledBitmap.getWidth(),
                ScaledBitmap.getHeight(), ScaledBitmap.getConfig());
        Canvas canvas = new Canvas(overlaybitmap);
        canvas.drawBitmap(ScaledBitmap, new Matrix(), null);
        canvas.drawBitmap(bit, new Matrix(), null);

        return overlaybitmap;
    }
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任何帮助将不胜感激.

Raj*_*ddy 54

你可以像这样组合两个位图

public static Bitmap overlay(Bitmap bmp1, Bitmap bmp2) {
    Bitmap bmOverlay = Bitmap.createBitmap(bmp1.getWidth(), bmp1.getHeight(), bmp1.getConfig());
    Canvas canvas = new Canvas(bmOverlay);
    canvas.drawBitmap(bmp1, new Matrix(), null);
    canvas.drawBitmap(bmp2, 0, 0, null);
    return bmOverlay;
}
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  • bmp1(500,500)和bmp2(400,400)是的我尝试了但是bmp1显示了他们的实际尺寸但是当我将bmp2变为(40,50)它根据bmp1保存时我想保存我使用手势放置图像的位置. .... (2认同)

小智 6

您可以将两个位图(即一个位图放在另一个位图上)组合在一起作为覆盖,请
尝试以下代码:

 public Bitmap bitmapOverlayToCenter(Bitmap bitmap1, Bitmap overlayBitmap) {
        int bitmap1Width = bitmap1.getWidth();
        int bitmap1Height = bitmap1.getHeight();
        int bitmap2Width = overlayBitmap.getWidth();
        int bitmap2Height = overlayBitmap.getHeight();

        float marginLeft = (float) (bitmap1Width * 0.5 - bitmap2Width * 0.5);
        float marginTop = (float) (bitmap1Height * 0.5 - bitmap2Height * 0.5);

        Bitmap finalBitmap = Bitmap.createBitmap(bitmap1Width, bitmap1Height, bitmap1.getConfig());
        Canvas canvas = new Canvas(finalBitmap);
        canvas.drawBitmap(bitmap1, new Matrix(), null);
        canvas.drawBitmap(overlayBitmap, marginLeft, marginTop, null);
        return finalBitmap;
    }  
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