按多列排序

Question

按多列排序

Bre*_*ews 8 sql sql-server sql-server-2005

我需要按两列排序数据,我该怎么做？

这是我的表:

Name   |  ImpFile   |  ImpTime
Sam      Imp01        2012-05-16 09:54:02.477
Ann      Imp01        2012-05-16 09:54:02.478
Mark     Imp01        2012-05-16 09:54:02.477
John     Import12     2012-05-16 09:55:37.384
Bart     Import12     2012-05-16 09:55:37.387
Sasha    Import12     2012-05-16 09:55:37.385

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我需要通过ImpTime和ImpName对此表进行排序,它应该如下所示:

Name   |  ImpFile   |  ImpTime
         Import12    2012-05-16 09:55:37.387
Bart     Import12    2012-05-16 09:55:37.387
John     Import12    2012-05-16 09:55:37.384
Sasha    Import12    2012-05-16 09:55:37.385
         Imp01       2012-05-16 09:54:02.478
Ann      Imp01       2012-05-16 09:54:02.478
Mark     Imp01       2012-05-16 09:54:02.477
Sam      Imp01       2012-05-16 09:54:02.477

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我正在使用此查询,但它没有按名称对表进行排序,当时间是多行的相同值时,只按名称排序.

select Name, ImpFile, ImpTime
from people
union
select distinct '', ImpFile, max(ImpTime)
from people 
group by ImpFile
order by ImpTime desc, Name

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这个查询给我这样的表:

Name   |  ImpFile   |  ImpTime
         Import12     2012-05-16 09:55:37.387
John     Import12     2012-05-16 09:55:37.384
Bart     Import12     2012-05-16 09:55:37.387
Sasha    Import12     2012-05-16 09:55:37.385
         Imp01        2012-05-16 09:54:02.478
Sam      Imp01        2012-05-16 09:54:02.477
Ann      Imp01        2012-05-16 09:54:02.478
Mark     Imp01        2012-05-16 09:54:02.477

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有没有办法同时按这两列排序？

编辑我使用时会发生什么order by ImpFile DESC, ImpTime desc？
它给了我一个像这样的结果表:

Name   |  ImpFile   |  ImpTime
         Import12    2012-05-16 09:55:37.387
         Imp01       2012-05-16 09:54:02.478
Bart     Import12    2012-05-16 09:55:37.387
John     Import12    2012-05-16 09:55:37.384
Sasha    Import12    2012-05-16 09:55:37.385
Ann      Imp01       2012-05-16 09:54:02.478
Mark     Imp01       2012-05-16 09:54:02.477
Sam      Imp01       2012-05-16 09:54:02.477

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Answer 1

Ari*_*ion 6

你为什么这样做:

order by ImpFile DESC, ImpTime desc

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不,它不会导致你所展示的内容.结果如下:

        Import12    2012-05-16 09:55:37.387
Bart    Import12    2012-05-16 09:55:37.387
Sasha   Import12    2012-05-16 09:55:37.387
John    Import12    2012-05-16 09:55:37.383
        Imp01       2012-05-16 09:54:02.477
Ann     Imp01       2012-05-16 09:54:02.477
Mark    Imp01       2012-05-16 09:54:02.477
Sam     Imp01       2012-05-16 09:54:02.477

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请看这里的例子

编辑

我有一个建议给你.也许是这样的:

测试数据

DECLARE @T TABLE(Name VARCHAR(100),ImpFile VARCHAR(100),ImpTime DATETIME)

INSERT INTO @T
    ([Name], [ImpFile], [ImpTime])
VALUES
    ('Sam', 'Imp01', '2012-05-16 09:54:02.477'),
    ('Ann', 'Imp01', '2012-05-16 09:54:02.478'),
    ('Mark', 'Imp01', '2012-05-16 09:54:02.477'),
    ('John', 'Import12', '2012-05-16 09:55:37.384'),
    ('Bart', 'Import12', '2012-05-16 09:55:37.387'),
    ('Sasha', 'Import12', '2012-05-16 09:55:37.385');

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询问

;WITH CTE
AS
(   
    SELECT
        ROW_Number() OVER(PARTITION BY  t.[ImpFile] 
                     ORDER BY t.[ImpTime] DESC) AS RowNbr,
        '' AS Name,
        t.ImpFile,
        t.[ImpTime]
    FROM
        @T AS t
)
SELECT
    CTE.Name,
    CTE.ImpFile,
    CTE.[ImpTime],
    0 as SortOrder
FROM
    CTE
WHERE
    CTE.RowNbr=1
UNION ALL
SELECT
    t.Name,
    t.ImpFile,
    t.[ImpTime],
    1 as SortOrder
FROM
    @T AS t
ORDER BY
    ImpFile DESC,SortOrder, ImpTime desc

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Answer 2

Mic*_*uen 5

获取每个组的领导者并按降序时间对其进行排序:

with grp(Name,ImpFile,TimeGroup,ImpTime) as 
(
  select cast(null as varchar(5)), ImpFile, max(ImpTime) as TimeGroup, 
         max(ImpTime) as ImpTime
  from people 
  group by ImpFile  
)
select * 
from grp
order by TimeGroup desc;

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输出:

NAME      IMPFILE   TIMEGROUP                     IMPTIME
(null)    Import12  2012-05-16 09:55:37.3870000   2012-05-16 09:55:37.3870000
(null)    Imp01     2012-05-16 09:54:02.4780000   2012-05-16 09:54:02.4780000

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然后加入追随者到领导者并获得领导者的时间(TimeGroup):

with grp(Name,ImpFile,TimeGroup,ImpTime) as 
(
  select cast(null as varchar(5)), ImpFile, max(ImpTime) as TimeGroup, 
         max(ImpTime) as ImpTime
  from people 
  group by ImpFile  

  union all

  select p.Name, p.ImpFile, ldr.TimeGroup, p.ImpTime
  from people p
  inner join grp ldr -- leader
  on ldr.name is null and ldr.ImpFile = p.ImpFile
)
select Name, ImpFile, ImpTime
from grp 
order by TimeGroup desc, Name

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输出:

NAME      IMPFILE   IMPTIME
(null)    Import12  2012-05-16 09:55:37.3870000
Bart      Import12  2012-05-16 09:55:37.3870000
John      Import12  2012-05-16 09:55:37.3840000
Sasha     Import12  2012-05-16 09:55:37.3850000
(null)    Imp01     2012-05-16 09:54:02.4780000
Ann       Imp01     2012-05-16 09:54:02.4780000
Mark      Imp01     2012-05-16 09:54:02.4770000
Sam       Imp01     2012-05-16 09:54:02.4770000

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查询的逻辑是,我们根据ImpFile将关注者(名字有些人)的时间与其领导者的时间(TimeGroup)对齐.领导者及其粉丝拥有相同的时间组,所以当我们按时间排序时,他们会互相依赖; 之后,我们按名称排序

现场测试:http://www.sqlfiddle.com/#!3/c7859/21

如果我们希望组长在其关注者之后出现,只需在ORDER BY上加上一个案例:

with grp(Name,ImpFile,TimeGroup,ImpTime) as 
(
  select cast(null as varchar(5)), ImpFile, max(ImpTime) as TimeGroup, 
         max(ImpTime) as ImpTime
  from people 
  group by ImpFile  

  union all

  select p.Name, p.ImpFile, ldr.TimeGroup, p.ImpTime
  from people p
  inner join grp ldr -- leader
  on ldr.name is null and ldr.ImpFile = p.ImpFile
)
select Name, ImpFile, ImpTime
from grp 
order by TimeGroup desc, 

  case 
  when Name is null then 2 -- leader last
  else 1 -- followers first
  end,

  Name

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输出:

NAME      IMPFILE   IMPTIME
Bart      Import12  2012-05-16 09:55:37.3870000
John      Import12  2012-05-16 09:55:37.3840000
Sasha     Import12  2012-05-16 09:55:37.3850000
(null)    Import12  2012-05-16 09:55:37.3870000
Ann       Imp01     2012-05-16 09:54:02.4780000
Mark      Imp01     2012-05-16 09:54:02.4770000
Sam       Imp01     2012-05-16 09:54:02.4770000
(null)    Imp01     2012-05-16 09:54:02.4780000

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现场测试:http://www.sqlfiddle.com/#!3/c7859/23

这个怎么运作:

with grp(Name,ImpFile,TimeGroup,ImpTime) as 
(
  select cast(null as varchar(5)), ImpFile, max(ImpTime) as TimeGroup, 
         max(ImpTime) as ImpTime
  from people 
  group by ImpFile  

  union all

  select p.Name, p.ImpFile, ldr.TimeGroup, p.ImpTime
  from people p
  inner join grp ldr -- leader
  on ldr.name is null and ldr.ImpFile = p.ImpFile
)
select *
from grp 
order by TimeGroup desc, Name;

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输出:

NAME      IMPFILE   IMPTIME                       TIMEGROUP
(null)    Import12  2012-05-16 09:55:37.3870000   2012-05-16 09:55:37.3870000
Bart      Import12  2012-05-16 09:55:37.3870000   2012-05-16 09:55:37.3870000
John      Import12  2012-05-16 09:55:37.3840000   2012-05-16 09:55:37.3870000
Sasha     Import12  2012-05-16 09:55:37.3850000   2012-05-16 09:55:37.3870000
(null)    Imp01     2012-05-16 09:54:02.4780000   2012-05-16 09:54:02.4780000
Ann       Imp01     2012-05-16 09:54:02.4780000   2012-05-16 09:54:02.4780000
Mark      Imp01     2012-05-16 09:54:02.4770000   2012-05-16 09:54:02.4780000
Sam       Imp01     2012-05-16 09:54:02.4770000   2012-05-16 09:54:02.4780000

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现场测试:http://www.sqlfiddle.com/#!3/c7859/25

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