我收到这个错误:
Index and length must refer to a location within the string.
Parameter name: length
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使用此代码:
string a1 = ddlweek.Text.Substring(0, 8);
string a3 = ddlweek.Text.Substring(10, 14);
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这是什么意思?
din*_*erm 13
如果字符串的长度(ddlweek)是23个字符或更少,您将收到此错误:
string ddlweek = "12345678901234567890123";//This is NOK
string a1 = ddlweek.Substring(0, 8);
string a3 = ddlweek.Substring(10, 14);
Console.WriteLine("a1="+a1);
Console.WriteLine("a3="+a3);
Console.ReadLine();
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该字符串应至少24个字符.您可以考虑添加一个if以确保一切正常..
string ddlweek = "123456789012345678901234";//This is OK
string a1 = ddlweek.Substring(0, 8);
string a3 = ddlweek.Substring(10, 14);
Console.WriteLine("a1="+a1);
Console.WriteLine("a3="+a3);
Console.ReadLine();
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这意味着您的ddlweek.Text字符串包含的字符数少于您在Substring(index, length).
例子:
if (ddlweek.Text.Length >= 8)
string a1 = ddlweek.Text.Substring(0, 8);
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