Osc*_*uch 20 core-data nspredicate nsfetchrequest ios
我试图用一个UISearchBar查询的多个属性NSManagedObject
我有一个NSManagedObject叫Person,每个人都有一个name和socialSecurity财产.现在我的代码可以为其中一个属性或另一个属性执行搜索(获取),但不能同时执行这两个属性.
- (void) performFetch
{
[NSFetchedResultsController deleteCacheWithName:@"Master"];
// Init a fetch request
NSFetchRequest *fetchRequest = [[NSFetchRequest alloc] init];
NSEntityDescription *entity = [NSEntityDescription entityForName:@"MainObject" inManagedObjectContext:self.managedObjectContext];
[fetchRequest setEntity:entity];
// Apply an ascending sort for the color items
//NSSortDescriptor *sortDescriptor = [[NSSortDescriptor alloc] initWithKey:@"Term" ascending:YES selector:nil];
NSSortDescriptor *sortDescriptor;
sortDescriptor = [[NSSortDescriptor alloc] initWithKey:@"fullName" ascending:YES selector:@selector(caseInsensitiveCompare:)];
NSArray *descriptors = [NSArray arrayWithObject:sortDescriptor];
[fetchRequest setSortDescriptors:descriptors];
// Recover query
NSString *query = self.searchDisplayController.searchBar.text;
//if (query && query.length) fetchRequest.predicate = [NSPredicate predicateWithFormat:@"Term contains[cd] %@", query];
if(searchValue==1)
{
if (query && query.length) fetchRequest.predicate = [NSPredicate predicateWithFormat:@"name contains[cd] %@", query];
}
else {
if (query && query.length) fetchRequest.predicate = [NSPredicate predicateWithFormat:@"socialSecurity contains[cd] %@", query];
}
// Init the fetched results controller
NSError *error;
self.fetchedResultsController = [[NSFetchedResultsController alloc] initWithFetchRequest:fetchRequest managedObjectContext:self.managedObjectContext sectionNameKeyPath:@"pLLetter" cacheName:nil];
self.fetchedResultsController.delegate = self;
if (![[self fetchedResultsController] performFetch:&error]) NSLog(@"Error: %@", [error localizedDescription]);
[self.tableView reloadData];
}
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我不知道如何把这两个属性放到这个陈述中......
if (query && query.length) fetchRequest.predicate = [NSPredicate predicateWithFormat:@"name contains[cd] %@", query];
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任何帮助或想法将不胜感激.
Mat*_*uch 34
你可以用一个NSCompoundPredicate.
像这样:
NSPredicate *predicateName = [NSPredicate predicateWithFormat:@"name contains[cd] %@", query];
NSPredicate *predicateSSID = [NSPredicate predicateWithFormat:@"socialSecurity contains[cd] %@", query];
NSArray *subPredicates = [NSArray arrayWithObjects:predicateName, predicateSSID, nil];
NSPredicate *orPredicate = [NSCompoundPredicate orPredicateWithSubpredicates:subPredicates];
request.predicate = orPredicate;
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有一NSCompoundPredicate对AND过:andPredicateWithSubpredicates:
Cap*_*uff 26
您可以NSPredicate使用常用的布尔操作数(如AND/OR)在多个搜索项中附加.
这样的事情应该可以解决问题.
[NSPredicate predicateWithFormat:@"name contains[cd] %@ OR ssid contains[cd] %@", query, query];
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希望有帮助:)
除了@Matthias的答案,您还可以使用NSCompoundPredicate进行这样的AND操作.
Obj-C - AND
NSPredicate *predicate1 = [NSPredicate predicateWithFormat:@"X == 1"];
NSPredicate *predicate2 = [NSPredicate predicateWithFormat:@"X == 2"];
NSPredicate *predicate = [NSCompoundPredicate andPredicateWithSubpredicates:@[predicate1, predicate2]];
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斯威夫特 - 和
let predicate1:NSPredicate = NSPredicate(format: "X == 1")
let predicate2:NSPredicate = NSPredicate(format: "Y == 2")
let predicate:NSPredicate = NSCompoundPredicate(andPredicateWithSubpredicates: [predicate1,predicate2] )
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斯威夫特3 - 和
let predicate1 = NSPredicate(format: "X == 1")
let predicate2 = NSPredicate(format: "Y == 2")
let predicateCompound = NSCompoundPredicate(type: .and, subpredicates: [predicate1,predicate2])
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Swift2的完整解决方案
let request = NSFetchRequest(entityName: "Location")
let subPredicate1 = NSPredicate(format: "(name = %@)", searchString)
let subPredicate2 = NSPredicate(format: "(street = %@)", searchString)
let subPredicate3 = NSPredicate(format: "(city = %@)", searchString)
request.predicate = NSCompoundPredicate(type: .OrPredicateType, subpredicates: [subPredicate1, subPredicate2, subPredicate3])
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