在PHP中创建一个json对象

an0*_*4rd 7 php json

我如何在PHP中创建一个与此类似的json对象?

{
    "employees": [
        { "firstName":"John" , "lastName":"Doe" }, 
        { "firstName":"Anna" , "lastName":"Smith" }, 
        { "firstName":"Peter" , "lastName":"Jones" }
    ]
}
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AD7*_*six 22

您创建一个数组,并将其传递给json_encode

$stuff = array(
    'employees' => array(
        array('firstName' => 'John', 'lastName' => 'Doe'),
        ....
    )
);

echo json_encode($stuff);
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