Ben*_*ey4 10 python networking webpage
我如何只simplehttpwebsite_content.html在访问时显示localhost:8080？所以我看不到我的filetree,只看到网页.所有这些文件都在同一个目录中.
simplehttpwebsite.py
#!/usr/bin/env python
import SimpleHTTPServer
import SocketServer
Handler = SimpleHTTPServer.SimpleHTTPRequestHandler
server = SocketServer.TCPServer(('0.0.0.0', 8080), Handler)
server.serve_forever()
simplehttpwebsite_content.html
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html>
<head>
<link rel="stylesheet" type="text/css" href="simplehttpwebsite_style.css">
</head>
<body>
This is my first web page
</body>
</html>
simplehttpwebsite_style.css
body{background-color:blue;}
Sus*_*Pal 23
您可以扩展SimpleHTTPServer.SimpleHTTPRequestHandler和覆盖do_GET要替换self.path为simplehttpwebpage_content.htmlif 的方法/.
#!/usr/bin/env python
import SimpleHTTPServer
import SocketServer
class MyRequestHandler(SimpleHTTPServer.SimpleHTTPRequestHandler):
def do_GET(self):
if self.path == '/':
self.path = '/simplehttpwebpage_content.html'
return SimpleHTTPServer.SimpleHTTPRequestHandler.do_GET(self)
Handler = MyRequestHandler
server = SocketServer.TCPServer(('0.0.0.0', 8080), Handler)
server.serve_forever()
自SimpleHTTPServer.SimpleHTTPRequestHandler扩展以来BaseHTTPServer.BaseHTTPRequestHandler,您可以阅读其文档以了解可用的方法和实例变量以及如何操作它们.
您可以找到path文档中提到的变量BaseHTTPServer.BaseHTTPRequestHandler.您可以找到do_GET()文档中提到的方法SimpleHTTPServer.SimpleHTTPRequestHandler.
这是我的shell的一些输出,以显示当我运行此程序然后我尝试访问时会发生什么 http://localhost:8080/
susam@swift:~/so$ ls
simplehttpwebpage_content.html simplehttpwebpage.py simplehttpwebsite_style.css
susam@swift:~/so$ python simplehttpwebpage.py
swift - - [19/Apr/2012 09:10:23] "GET / HTTP/1.1" 200 -
swift - - [19/Apr/2012 09:10:26] "GET /simplehttpwebsite_style.css HTTP/1.1" 200 -