目前VariableService是@Autowired在我的控制器.
我意识到我可以实现这个课程ParameterizedType来消除这个错误,但我担心我可能会朝着错误的方向前进.有没有更好的方法来做到这一点,还是我需要咬紧牙关并实施ParameterizedType方法?
org.springframework.beans.factory.BeanCreationException:创建名为'contentController'的bean时出错:注入自动连接的依赖项失败; 嵌套异常是org.springframework.beans.factory.BeanCreationException:无法自动装配字段:private com.fettergroup.cmt.service.VariableService com.fettergroup.cmt.web.ContentController.variableService; 嵌套异常是org.springframework.beans.factory.BeanCreationException:在ServletContext资源[/WEB-INF/dispatcher-servlet.xml]中定义创建名为'variableService'的bean时出错:bean的实例化失败; 嵌套异常是org.springframework.beans.BeanInstantiationException:无法实例化bean类[com.fettergroup.cmt.service.VariableService]:构造函数抛出异常; 嵌套异常是java.lang.ClassCastException:java.lang.Class无法强制转换为java.lang.reflect.ParameterizedType
可变服务
public class VariableService extends EntityService {
public VariableService () {
super.setEntityRepository(new VariableRepository());
}
}
Run Code Online (Sandbox Code Playgroud)
EntityService
public abstract class EntityService<T> {
public EntityRepository<T> entityRepository;
public T create(T entity) {
return entityRepository.create(entity);
}
public T update(T entity) {
return entityRepository.update(entity);
}
public void delete(T entity) {
entityRepository.delete(entity);
}
public void setEntityRepository(EntityRepository<T> entityRepository) {
this.entityRepository = entityRepository;
}
}
Run Code Online (Sandbox Code Playgroud)
变量存储库
public class VariableRepository extends EntityRepository {
}
Run Code Online (Sandbox Code Playgroud)
EntityRepository
@Repository
public abstract class EntityRepository<T> {
//the equivalent of User.class
protected Class<T> entityClass;
@PersistenceContext(type= PersistenceContextType.TRANSACTION)
public EntityManager entityManager;
public EntityRepository () {
//Get "T" and assign it to this.entityClass
ParameterizedType genericSuperclass = (ParameterizedType) getClass().getGenericSuperclass();
this.entityClass = (Class<T>) genericSuperclass.getActualTypeArguments()[0];
}
/**
* Create this entity
* @param t
* @return
*/
public T create(T t) {
entityManager.persist(t);
return t;
}
/**
* Update this entity
* @param t
* @return
*/
public T update(T t) {
return entityManager.merge(t);
}
/**
* Delete this entity
* @param entity
*/
public void delete(T t) {
t = this.update(t);
entityManager.remove(t);
}
public void setEntityManager(EntityManager entityManager) {
this.entityManager = entityManager;
}
}
Run Code Online (Sandbox Code Playgroud)
Att*_*cus 16
只是说,这是一个非常糟糕的设计,用于确定实体类型.你应该做以下事情,而不是依靠反射来推断它的类def ..它不仅会摆脱那个错误,而且会整体更清洁,在低水平,比反射更快(不是它真的是一个问题).
@Repository
public abstract class EntityRepository<T>{
protected Class<T> entityClass;
public EntityRepository(Class<T> entityClass){
this.entityClass = entityClass;
}
//...
}
public class UserEntityRepository extends EntityRepository<User>{
public UserEntityRepository(){
super(User.class);
}
}
Run Code Online (Sandbox Code Playgroud)
EntityRepository不是ParameterizedType类型.该类仅扩展ParameterizedType.如果spring通过cglib代理你,这也是可能的
我们需要检查班级的父母
public EntityRepository () {
//Get "T" and assign it to this.entityClass
Type genericSuperClass = getClass().getGenericSuperclass();
ParameterizedType parametrizedType = null;
while (parametrizedType == null) {
if ((genericSuperClass instanceof ParameterizedType)) {
parametrizedType = (ParameterizedType) genericSuperClass;
} else {
genericSuperClass = ((Class<?>) genericSuperClass).getGenericSuperclass();
}
}
entityClass = (Class<T>) parametrizedType.getActualTypeArguments()[0];
}
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
30593 次 |
| 最近记录: |