从另一个表中选择带有id的行

Jür*_*aul 29 mysql sql database

我们叫这个表terms_relation:

+---------+----------+-------------+------------+------------+--+
| term_id | taxonomy | description | created_at | updated_at |  |
+---------+----------+-------------+------------+------------+--+
|       1 | categ    | non         | 3434343434 |   34343433 |  |
|       2 | categ    | non         | 3434343434 | 3434343434 |  |
|       3 | tag      | non         | 3434343434 | 3434343434 |  |
|       4 | tag      | non         | 3434343434 | 3434343434 |  |
+---------+----------+-------------+------------+------------+--+
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这是表terms:

+----+-------------+-------------+
| id |    name     |    slug     |
+----+-------------+-------------+
|  1 | hello       | hello       |
|  2 | how are you | how-are-you |
|  3 | tutorial    | tutorial    |
|  4 | the end     | the-end     |
+----+-------------+-------------+
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我该如何选择表中的所有行terms和表terms_relation它的分类表terms_relationcateg?我是否需要两个查询,或者我可以使用一个join语句?

gah*_*cep 72

试试这个(子查询):

SELECT * FROM terms WHERE id IN 
   (SELECT term_id FROM terms_relation WHERE taxonomy = "categ")
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或者你可以尝试这个(加入):

SELECT t.* FROM terms AS t 
   INNER JOIN terms_relation AS tr 
   ON t.id = tr.term_id AND tr.taxonomy = "categ"
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如果要从两个表中接收所有字段:

SELECT t.id, t.name, t.slug, tr.description, tr.created_at, tr.updated_at 
  FROM terms AS t 
   INNER JOIN terms_relation AS tr 
   ON t.id = tr.term_id AND tr.taxonomy = "categ"
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  • 太棒了,你们两个都是对的。很难选择,谢谢! (2认同)

Jos*_*mit 17

您可以使用子查询:

SELECT *
FROM terms
WHERE id IN (SELECT term_id FROM terms_relation WHERE taxonomy='categ');
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如果您需要显示两个表中的所有列:

SELECT t.*, tr.*
FROM terms t, terms_relation tr
WHERE t.id = tr.term_id
AND tr.taxonomy='categ'
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