iPhone - 从Latitude和Longtiude获取城市名称

Question

我想在我的iPhone应用程序中获取当前城市名称.

我目前正在使用CLLocationManager获取纬度和经度,而不是将我的坐标传递给CLGeocoder.

    CLGeocoder * geoCoder = [[CLGeocoder alloc] init];
    [geoCoder reverseGeocodeLocation:location completionHandler:^(NSArray *placemarks, NSError *error) {
        for (CLPlacemark * placemark in placemarks) {
            UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Current City" message:[NSString stringWithFormat:@"Your Current City:%@",[placemark locality]] delegate:self cancelButtonTitle:@"OK" otherButtonTitles:@"Cancel", nil];
            [alert  show];
        }  
    }];

这在iOS 5.0中运行良好,但在iOS 4.3中无效.

作为替代方案,我开始使用Google Web服务

-(void)findLocationFor:(NSString *)latitudeStr 
          andLontitude:(NSString *)longtitudeStr{
    if ([self connectedToWiFi]){
        float latitude  = [latitudeStr floatValue];
        float longitude = [longtitudeStr floatValue];
        NSMutableDictionary *parameters = [NSMutableDictionary dictionaryWithObjectsAndKeys: 
                                           [NSString stringWithFormat:@"%f,%f", latitude, longitude], @"latlng", nil];
        NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:@"http://maps.googleapis.com/maps/api/geocode/json"]];
        [parameters setValue:@"true" forKey:@"sensor"];
        [parameters setValue:[[NSLocale currentLocale] objectForKey:NSLocaleLanguageCode] forKey:@"language"];
        NSMutableArray *paramStringsArray = [NSMutableArray arrayWithCapacity:[[parameters allKeys] count]];

        for(NSString *key in [parameters allKeys]) {
            NSObject *paramValue = [parameters valueForKey:key];
            [paramStringsArray addObject:[NSString stringWithFormat:@"%@=%@", key, paramValue]];
        }

        NSString *paramsString = [paramStringsArray componentsJoinedByString:@"&"];
        NSString *baseAddress = request.URL.absoluteString;
        baseAddress = [baseAddress stringByAppendingFormat:@"?%@", paramsString];
        [request setURL:[NSURL URLWithString:baseAddress]];

        NSError        *error    = nil;
        NSURLResponse  *response = nil;
        NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];
        if (response == nil) {
            if (error != nil) {
            }
        }
        else {
            NSDictionary *responseDict = [returnData objectFromJSONData];
            NSArray *resultsArray = [responseDict valueForKey:@"results"]; 
            NSMutableArray *placemarksArray = [NSMutableArray arrayWithCapacity:[resultsArray count]];
            for(NSDictionary *placemarkDict in resultsArray){
                NSDictionary *coordinateDict = [[placemarkDict valueForKey:@"geometry"] valueForKey:@"location"];

                float lat = [[coordinateDict valueForKey:@"lat"] floatValue];
                float lng = [[coordinateDict valueForKey:@"lng"] floatValue];

                NSMutableDictionary *dict = [[NSMutableDictionary alloc] init];
                [dict setObject:[NSString stringWithFormat:@"%.f",lat] forKey:@"latitude"];
                [dict setObject:[NSString stringWithFormat:@"%.f",lng] forKey:@"longitude"];
                [dict setObject:[placemarkDict objectForKey:@"formatted_address"] forKey:@"address"];

                [placemarksArray addObject:dict];
                [dict release];
            }
            NSDictionary *placemark = [placemarksArray objectAtIndex:0];
        }
    }
}

但我得到的回答太长,意味着我仍然无法得到城市名称,因为在某些情况下,这个网络服务提供有关坐标的所有其他信息,期望城市名称.

有人能帮帮我吗？

Answer 1

根据文档,CLGeocoder在iOS5下不起作用.你需要采取另一种方式来支持iOS4和iOS5.

您可以查看MKReverseGeocoder,但它在iOS5中已弃用,但仍可用于此目的.如需确认,您可以查看所谓的问题

+(NSString *)getAddressFromLatLon:(double)pdblLatitude withLongitude:(double)pdblLongitude
{
    NSString *urlString = [NSString stringWithFormat:@"http://maps.google.com/maps/geo?q=%f,%f&output=csv",pdblLatitude, pdblLongitude];
    NSError* error;
    NSString *locationString = [NSString stringWithContentsOfURL:[NSURL URLWithString:urlString] encoding:NSASCIIStringEncoding error:&error];
    locationString = [locationString stringByReplacingOccurrencesOfString:@"\"" withString:@""];
    return [locationString substringFromIndex:6];
}

您可以使用此功能从纬度,经度获取地址.您可以根据要求进行更改.我们把它作为Class方法,所以我们可以直接使用它

NSString *strAddressFromLatLong = [CLassName getAddressFromLatLon:37.484848 withLongitude:74.48489];

编辑

请停止使用上述功能,因为它已在评论中报告已停止工作(未经我测试).我建议开始使用SVGeocoder

Answer 2

我正在使用它并获取邮政编码和城市名称.修改了Janak添加的方法.

- (void) getAddressFromLatLon:(CLLocation *)bestLocation
{
    NSLog(@"%f %f", bestLocation.coordinate.latitude, bestLocation.coordinate.longitude);
    CLGeocoder *geocoder = [[CLGeocoder alloc] init] ;
    [geocoder reverseGeocodeLocation:bestLocation
                   completionHandler:^(NSArray *placemarks, NSError *error)
    {
        if (error){
            NSLog(@"Geocode failed with error: %@", error);
            return;
        }
        CLPlacemark *placemark = [placemarks objectAtIndex:0];
        NSLog(@"placemark.ISOcountryCode %@",placemark.ISOcountryCode);
        NSLog(@"locality %@",placemark.locality);
        NSLog(@"postalCode %@",placemark.postalCode);

    }];

}

Answer 3

这个对我有用 :)

CLGeocoder *ceo = [[CLGeocoder alloc]init];
CLLocation *loc = [[CLLocation alloc]initWithLatitude:26.93611 longitude:26.93611];

[ceo reverseGeocodeLocation: loc completionHandler:
 ^(NSArray *placemarks, NSError *error) {
     CLPlacemark *placemark = [placemarks objectAtIndex:0];
     NSLog(@"placemark %@",placemark);
     //String to hold address
     NSString *locatedAt = [[placemark.addressDictionary valueForKey:@"FormattedAddressLines"] componentsJoinedByString:@", "];
     NSLog(@"addressDictionary %@", placemark.addressDictionary);

     NSLog(@"placemark %@",placemark.region);
     NSLog(@"placemark %@",placemark.country);  // Give Country Name
     NSLog(@"placemark %@",placemark.locality); // Extract the city name
     NSLog(@"location %@",placemark.name);
     NSLog(@"location %@",placemark.ocean);
     NSLog(@"location %@",placemark.postalCode);
     NSLog(@"location %@",placemark.subLocality);

     NSLog(@"location %@",placemark.location);
     //Print the location to console
     NSLog(@"I am currently at %@",locatedAt);
 }];

Answer 4

//Place below parser code where you are reading latlng and place your latlng in the url
NSXMLParser *parser = [[NSXMLParser alloc]initWithContentsOfURL:[NSURL URLWithString:@"http://maps.googleapis.com/maps/api/geocode/xml?latlng=40.714224,-73.961452&sensor=false"]];
[parser setDelegate:self];
[parser parse];

// Below are the delegates which will get you the exact address easyly
-(void)parser:(NSXMLParser *)parser didStartElement:(NSString *)elementName namespaceURI:(NSString *)namespaceURI qualifiedName:(NSString *)qName attributes:(NSDictionary *)attributeDict
{    
    if([elementName isEqualToString:@"formatted_address"]){
        got = YES; //got is a BOOL
    }
}

-(void)parser:(NSXMLParser *)parser foundCharacters:(NSString *)string
{
    if(got){
        NSLog(@"the address is = %@",string);
    }
}

-(void)parser:(NSXMLParser *)parser didEndElement:(NSString *)elementName namespaceURI:(NSString *)namespaceURI qualifiedName:(NSString *)qName{
}

//what we are doing is using xmlparser to parse the data which we get through the google map api copy above link and use in browser you will see the xml data brought

抱歉,我的英语不好希望它会帮助你