django-pagination可以每页多个分页吗？

Question

如果它不能那么有任何其他替代品(Django的原生分页或替代包)允许每页多个分页？

我想显示一个大约5个对象的列表,每个对象都有自己的分页上下文.

为方便起见,这里是django-pagination的文档.

Answer 1

我知道这篇文章很老,但它仍然有用.以下内容适用于Django 1.9.

这是怎么做的,

views.py

def myview():
    Model_one = Model.objects.all()
    paginator = Paginator(Model_one, 6)
    page = request.GET.get('page1')
    try:
        Model_one = paginator.page(page)
    except PageNotAnInteger:
        Model_one = paginator.page(1)
    except EmptyPage:
        Model_one = paginator.page(paginator.num_pages)

    Model_two = Model_other.objects.all()
    paginator = Paginator(Model_two, 6)
    page = request.GET.get('page2')
    try:
        Model_two = paginator.page(page)
    except PageNotAnInteger:
        Model_two = paginator.page(1)
    except EmptyPage:
        Model_two = paginator.page(paginator.num_pages)

    context = {'Model_one': Model_one, 'Model_two': Model_two}
    return render(request, 'template.html', context)

上面重要的是'page1'和'page2'.

在模板中,

    {% if model_one %}
      <div class="col-md-12 well">
        {% for item in model_one %}
        ..... iterates through model_one.....
        {% endfor %}
        <span class="step-links pagination">
            {% if model_one.has_previous %}
                <a href="?page1={{ model_one.previous_page_number }}"> previous </a>
            {% endif %}
            <span class="current">
                Page {{ model_one.number }} of {{ model_one.paginator.num_pages }}
            </span>
            {% if model_one.has_next %}
                <a href="?page1={{ model_one.next_page_number }}"> next </a>
            {% endif %}
        </span>
      </div>
      {% endif %}
      {% if model_two %}
      <div class="col-md-12 well">
        {% for item in model_two %}
        ..... iterates through model_two.....
        {% endfor %}
        <span class="step-links pagination">
            {% if model_two.has_previous %}
                <a href="?page2={{ model_two.previous_page_number }}"> previous </a>
            {% endif %}
            <span class="current">
                Page {{ model_two.number }} of {{ model_two.paginator.num_pages }}
            </span>
            {% if model_two.has_next %}
                <a href="?page2={{ model_two.next_page_number }}"> next </a>
            {% endif %}
        </span>
      </div>
      {% endif %}

再次使用'page1'和'page2'来区分每个模型的分页.

Answer 2

当然,这是可能的.我不能说django-pagination包,但绝对可以使用默认的Django Paginator类.您可以在视图中创建任意数量的内容.只需选择不同的GET参数来指定每个参数的页面,你就可以了.