将路径字符串拆分为驱动器,路径和文件名部分

Question

我是python和编码的新手.我试图从一个文本文件中读取每行都有路径名.我想逐行读取文本文件,并将行字符串拆分为驱动器,路径和文件名.

这是我到目前为止的代码:

import os,sys, arcpy

## Open the file with read only permit
f = open('C:/Users/visc/scratch/scratch_child/test.txt')

for line in f:
    (drive,path,file) = os.path.split(line)

    print line.strip()
    #arcpy.AddMessage (line.strip())
    print('Drive is %s Path is %s and file is %s' % (drive, path, file))

我收到以下错误:

File "C:/Users/visc/scratch/simple.py", line 14, in <module>
    (drive,path,file) = os.path.split(line)
ValueError: need more than 2 values to unpack

当我只想要路径和文件名时,我没有收到此错误.

Answer 1

你需要先使用os.path.splitdrive:

with open('C:/Users/visc/scratch/scratch_child/test.txt') as f:
    for line in f:
        drive, path = os.path.splitdrive(line)
        path, filename = os.path.split(path)
        print('Drive is %s Path is %s and file is %s' % (drive, path, filename))

笔记:

• 该with语句确保文件在块结束时关闭(文件也在垃圾收集器吃它们时关闭,但使用with通常是好的做法
• 你不需要括号 - os.path.splitdrive(path)返回一个元组,这将自动解压缩
• file 是标准命名空间中的类的名称,您可能不应该覆盖它:)

Answer 2

您可以使用os.path.splitdrive()来获取驱动器,然后使用path.split()来获取其余部分.

## Open the file with read only permit
f = open('C:/Users/visc/scratch/scratch_child/test.txt')

for line in f:
    (drive, path) = os.path.splitdrive(line)
    (path, file)  = os.path.split(path)

    print line.strip()
    print('Drive is %s Path is %s and file is %s' % (drive, path, file))