TIM*_*MEX 12 html python regex xml
假设我的内部有HTML <p>和<br>标签.然后,我将剥离HTML来清理标签.如何将它们变成换行符？
我正在使用Python的BeautifulSoup库,如果这有帮助的话.
Mik*_*ton 15
没有一些细节,很难确定这完全符合你的要求,但这应该给你一个想法......它假设你的b标签包含在p元素中.
from BeautifulSoup import BeautifulSoup
import types
def replace_with_newlines(element):
text = ''
for elem in element.recursiveChildGenerator():
if isinstance(elem, types.StringTypes):
text += elem.strip()
elif elem.name == 'br':
text += '\n'
return text
page = """<html>
<body>
<p>America,<br>
Now is the<br>time for all good men to come to the aid<br>of their country.</p>
<p>pile on taxpayer debt<br></p>
<p>Now is the<br>time for all good men to come to the aid<br>of their country.</p>
</body>
</html>
"""
soup = BeautifulSoup(page)
lines = soup.find("body")
for line in lines.findAll('p'):
line = replace_with_newlines(line)
print line
运行此结果导致......
(py26_default)[mpenning@Bucksnort ~]$ python thing.py
America,
Now is the
time for all good men to come to the aid
of their country.
pile on taxpayer debt
Now is the
time for all good men to come to the aid
of their country.
(py26_default)[mpenning@Bucksnort ~]$
这是@Mike Pennington's Answer 的python3 版本（它真的很有帮助），我做了一个垃圾重构。
def replace_with_newlines(element):
text = ''
for elem in element.recursiveChildGenerator():
if isinstance(elem, str):
text += elem.strip()
elif elem.name == 'br':
text += '\n'
return text
def get_plain_text(soup):
plain_text = ''
lines = soup.find("body")
for line in lines.findAll('p'):
line = replace_with_newlines(line)
plain_text+=line
return plain_text
要使用它，只需将 Beautifulsoup 对象传递给 get_plain_text 方法。
soup = BeautifulSoup(page)
plain_text = get_plain_text(soup)
get_text 似乎可以满足您的需求
>>> from bs4 import BeautifulSoup
>>> doc = "<p>This is a paragraph.</p><p>This is another paragraph.</p>"
>>> soup = BeautifulSoup(doc)
>>> soup.get_text(separator="\n")
u'This is a paragraph.\nThis is another paragraph.'