yes*_*aaj 4 c++ arrays pointers strcpy
#include <cstring>
int main()
{
char *pName = new char[10];
char dummy[] = "dummy";
strcpy(pName + 0,dummy);//how this is different from -->this works
strcpy(pName[0],dummy);//this one...--> error C2664: 'strcpy' :
//cannot convert parameter 1
//from 'char' to 'char *'
}
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Dan*_*oof 12
你得到错误的原因是因为strcpy需要一个指向char(char*)的指针,而不是char值(这是pName [0]是什么)