单击时保持Bootstrap下拉列表打开

Question

我使用bootstrap下拉作为购物车.在购物车中是"删除产品"按钮(链接).如果我单击它,我的shoppingcart脚本将删除该产品,但菜单会消失.反正有办法阻止这种情况吗？我尝试了e.startPropagation,但这似乎不起作用:

<div id="shoppingcart" class="nav-collapse cart-collapse">
 <ul class="nav pull-right">
  <li class="dropdown open">
    <a href="#" data-toggle="dropdown" class="dropdown-toggle">Totaal:
    &acirc;&sbquo;&not; 43,00</a>

    <ul class="dropdown-menu">
      <li class="nav-header">Pakketten</li>

      <li>
       <span class="quantity">1x</span>
       <span class="product-name">Test Product </span>
       <span class="product-remove"><a class="removefromcart" packageid="4" href="#">x</a>
        </span></li>

      <li><a href="#">Total: &euro; 43,00</a></li>

      <li><a href="/checkout">Checkout</a></li>
    </ul>
  </li>
</ul>

正如你可以看到带有class ="dropwdown-toggle"的元素使它成为一个下拉列表.另一个想法是我只是通过编程方式重新打开它.因此,如果有人可以解释我如何以编程方式打开Bootstrap下拉列表,那将会很有帮助!

Answer 1

尝试删除按钮本身的传播,如下所示:

$('.dropdown-menu a.removefromcart').click(function(e) {
    e.stopPropagation();
});

编辑

以下是上述解决方案的评论演示:

http://jsfiddle.net/andresilich/E9mpu/

相关代码:

JS

$(".removefromcart").on("click", function(e){
    var fadeDelete = $(this).parents('.product');
    $(fadeDelete).fadeOut(function() {
        $(this).remove();
    });

    e.stopPropagation();
});

HTML

<div id="shoppingcart" class="nav-collapse cart-collapse">
 <ul class="nav pull-right">
  <li class="dropdown open">
    <a href="#" data-toggle="dropdown" class="dropdown-toggle">Totaal:
    &acirc;&sbquo;&not; 43,00</a>

    <ul class="dropdown-menu">
      <li class="nav-header">Pakketten</li>
        <li class="product">
            <span class="product-remove"><a class="removefromcart" packageid="2" href="#"><i class="icon-remove"></i></a></span>
            <span class="product-name">Test Product </span>
            <span class="quantity"><span class="badge badge-inverse">1</span></span>
        </li>
        <li class="product">
            <span class="product-remove"><a class="removefromcart" packageid="2" href="#"><i class="icon-remove"></i></a></span>
            <span class="product-name">Test Product </span>
            <span class="quantity"><span class="badge badge-inverse">10</span></span>
        </li>
        <li class="product">
            <span class="product-remove"><a class="removefromcart" packageid="2" href="#"><i class="icon-remove"></i></a></span>
            <span class="product-name">Test Product </span>
            <span class="quantity"><span class="badge badge-inverse">8</span></span>
        </li>
        <li class="product">
            <span class="product-remove"><a class="removefromcart" packageid="2" href="#"><i class="icon-remove"></i></a></span>
            <span class="product-name">Test Product </span>
            <span class="quantity"><span class="badge badge-inverse">3</span></span>
        </li>
        <li class="product">
            <span class="product-remove"><a class="removefromcart" packageid="2" href="#"><i class="icon-remove"></i></a></span>
            <span class="product-name">Test Product </span>
            <span class="quantity"><span class="badge badge-inverse">4</span></span>
        </li>
        <li class="divider"></li>
        <li><a href="#">Total: &euro; 43,00</a></li>
        <li><a href="/checkout">Checkout</a></li>
    </ul>
  </li>
</ul>

Answer 2

这个答案只是接受答案的旁注.感谢OP和Andres的问答,它解决了我的问题.然而,后来,我需要在我的下拉列表中使用动态添加的项目.遇到这个问题的任何人也可能会对Andres的变体感兴趣,该解决方案既适用于初始元素,也适用于页面加载后添加到下拉列表中的元素:

$(function() {
    $("ul.dropdown-menu").on("click", "[data-keepOpenOnClick]", function(e) {
        e.stopPropagation();
    });
});

或者,对于动态创建的下拉菜单:

$(document).delegate("ul.dropdown-menu [data-keepOpenOnClick]", "click", function(e) {
    e.stopPropagation();
});

然后根据您的具体情况,将data-keepOpenOnClick属性放在任何<li>标记或其子元素中的任何位置.例如:

<ul class="dropdown-menu">
    <li>
        <-- EG 1: Do not close when clicking on the link -->
        <a href="#" data-keepOpenOnClick>
            ...
        </a>
    </li>
    <li>
        <-- EG 2: Do not close when clicking the checkbox -->
        <input type="checkbox" data-keepOpenOnClick> Pizza
    </li>

    <-- EG 3: Do not close when clicking the entire LI -->
    <li data-keepOpenOnClick>
        ...
    </li>
</ul>

Answer 3

简而言之,你可以试试这个.它对我有用.

<span class="product-remove">
  <a class="removefromcart" onclick=" event.stopPropagation();" packageid="4" href="#">x</a>
  </span>

Answer 4

在bootstrap 4上，当您在下拉菜单中放置一个表单时，在其中单击时它不会折叠。

因此，这对我来说最有效：

<div class="dropdown">
    <!-- toggle button/link -->
    <div class="dropdown-menu">
        <form>
            <!-- content -->
        </form>
    </div>
</div>

Answer 5

show当您为菜单提供类时，菜单就会打开，因此您可以自己实现该功能，而无需使用data-toggle="dropdown".

<div class="dropdown">
  <button class="btn btn-secondary" type="button">
    Dropdown button
  </button>
  <div class="dropdown-menu">
    <a class="dropdown-item" href="#">Action</a>
    <a class="dropdown-item" href="#">Another action</a>
    <a class="dropdown-item" href="#">Something else here</a>
  </div>
</div>
<div id="overlay"></div>

#overlay{
  position: absolute;
  width: 100%;
  height: 100%;
  top: 0;
  left: 0;
  z-index: 1000;
  display: none;
}

#overlay.show{
  display: block;
}

.dropdown-menu{
  z-index: 1001;
}

$('button, #overlay').on('click', function(){
  $('.dropdown-menu, #overlay').toggleClass('show')
})

在codepen中尝试一下。