Dev*_*xon 24 javascript jquery html5 range
嘿jquery和hmtl5范围有点麻烦.我试着在改变时获取值,但事件监听器没有捕获它.目前我的代码是:
HTML
html += '<li>Apply Credits: <input type="range" min="0" max="'+credits+'" name="discount_credits" id="discount_credits" /> <span>'+credits+'</span></li>'
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JS是:
$('#discount_credits').mousewheel( function() {
alert('it changed!');
alert('new value = ' + $(this).val());
});
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我也试过了
$('#discount_credits').change( function() {
alert('it changed!');
alert('new value = ' + $(this).val());
});
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似乎都没有用.难道我做错了什么?
Bri*_*ian 30
$('input[type=range]').on('input', function () {
$(this).trigger('change');
});
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这会change在每个input事件中触发事件.
我假设您的跨度有一个 id:<span id="slidernumber">...</span>
让我们还假设您有几个滑块,并且您希望在移动其中任何一个时看到文本更改:
<li>
Apply Credits1:
<input type="range" min="0" max="100"
name="discount_credits1" id="discount_credits"
/>
</li>
<li>
Apply Credits2:
<input type="range" min="0" max="100"
name="discount_credits2" id="discount_credits"
/>
</li>
<span id="slidernumber">50</span>
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尝试这个:
$(document).ready(function(){
$("[type=range]").change(function(){
var newval=$(this).val();
$("#slidernumber").text(newval);
});
});
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http://jsfiddle.net/MahshidZeinaly/CgQ5c/
现在让我们假设您有几个滑块,但是如果移动了其中的一个,您希望看到文本更改。(我假设它是因为范围输入在 li 标签内,并且您给它起了一个名字):
<li>
Apply Credits1:
<input type="range" min="0" max="100"
name="discount_credits1" id="discount_credits"
/>
<span id="slidernumber">50</span>
</li>
<li>
Apply Credits2:
<input type="range" min="0" max="100"
name="discount_credits2" id="discount_credits"
/>
<span id="slidernumber">50</span>
</li>
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尝试这个:
$(document).ready(function(){
$("[type=range]").change(function(){
var newv=$(this).val();
$(this).next().text(newv);
});
});
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http://jsfiddle.net/MahshidZeinaly/2pe7P/1/
on Change 事件似乎对我来说工作正常:http ://jsfiddle.net/zV3xD/7/
\n\n<input type="range" min="0" max="100" name="discount_credits" id="discount_credits" />\n\n<span id="newValue" value="0">0</span>\n\n$(\'#discount_credits\').change( function() {\n var newValue = this.value; \n $(\'#newValue\').html(newValue);\n});\xe2\x80\x8b\nRun Code Online (Sandbox Code Playgroud)\n\n或者你可以尝试这样的事情:
\n\n<form oninput="result.value=parseInt(a.value)">\n <input type="range" name="a" value="50" /> =\n <output name="result">0</output>\n</form>\nRun Code Online (Sandbox Code Playgroud)\n\n使用output此处的示例:https ://developer.mozilla.org/en-US/docs/Web/HTML/Element/output
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