Google Place API - 如何检索营业时间

Question

有办法获得谷歌的开放时间吗？我在几个论坛和文档中寻找,但我没有发现任何东西(也许只有foursquare API暴露了这些信息)

谷歌没有公开这些信息？

是否有任何服务暴露这个？(facebook地方,yelp,ecc ..)

非常感谢所有回复

阿尔贝托

Answer 1

我想这现在有可能:

https://developers.google.com/places/documentation/details#PlaceDetailsResults

如果您不想制作自己的Places API密钥或安装节点,请参阅此要点以获取示例输出.

var request = require('request');
// $ npm install request
// Test code to demonstrate parsing operating hours from Google Places
// https://developers.google.com/places/documentation/details#PlaceDetailsResults

// most establishments specify one set of hours per day:
var testRef = 'CnRoAAAAhWUhxi1GkTSCMDMb2piX2JgQzcMv1v6Bv1rDWAINnWrI6T_Vkn3KRpnI5rTd2NI2f0zy4R8n6vRDoj-qTewKa3r70riORCUF-HNU1FLtI3MHNSw8z0_6fBni6hTuXCsGw1SD44I85ha9GVZOZlAS_hIQuNBJmgTHh9bCC4XvdLiDCBoUfmY1ozj0FW-TvurbmryBdwAvoPo';

// 24 hour restaurants only have one period with open:0000 and no close
var _24hrRef = 'CnRpAAAAcKNSNO0jxSONMAPx7EjG6BdgqhWbzDh1rOWM8I1HJZikRYPxW4L1A1ZwH4HEEBy5diKyXT1nRs2a7cxZK7S4oOr5HrTKewV_WGYdy-CuumuwLzSeckgXWvRdIRCW49JXUeJsqhkhtATHyyIDUYWW4RIQ38ZaUuG8A3WbRrsHLwmwDRoUfmtzSsfki7v8iBmUAZgrUIoVOt0'

// Restaurants that are closed on some days will have fewer than 7 open:close pairs

getPlaceDetails(_24hrRef, function(err, result){
  if(err){ 
    return console.log('Request error: '+err+result);
  };
  console.log('Request successful:')
  console.log(JSON.stringify(result.opening_hours, null, 2));
});

function getPlaceDetails(ref,callback){
  var config = {   
    uri:'https://maps.googleapis.com/maps/api/place/details/json',
    qs: {
      key: "SOME-VALID-GOOGLEPLACES-API-KEY",
      // Generate a new Simple API key and plug it in
      // https://code.google.com/apis/console
      reference:ref,
      sensor:'false',
    }
  };
  request(config, function(err, response, body){
    if(err){ return callback(err) };
    var res = JSON.parse(body);
    switch(res.status){
      case "OK":           return callback(null, res.result);
      case "ZERO_RESULTS": return callback(null, res.result);
      default:             return callback(res.status, body);
    };
  });
};