我有一个问题,检索列值,如依赖于其他列,我试图用外连接和嵌套选择,但我想我找不到我的脑袋里的解决方案
Categories Table:
ID Name ParentID
--------------------------------
1 Software NULL
2 Domains NULL
3 Games NULL
4 Accounts NULL
5 Others NULL
6 Security Software 1
7 Operating Systems 1
8 Browsers 1
9 Developer Tools 1
10 .com Domains 2
11 .net Domains 2
12 .org Domains 2
13 Online Games 3
14 PC Games 3
15 PS Games 3
16 RapidShare Accounts 4
17 4shared Account 4
18 Web Templates 5
19 Flash Intros 5
20 Firewall 6
21 Antivirus 6
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我想做什么来显示父类别名称而不是父ID
像那样
ID Name ParentID
--------------------------------
1 Software NULL
2 Domains NULL
3 Games NULL
4 Accounts NULL
5 Others NULL
6 Security Software Software
7 Operating Systems Software
8 Browsers Software
9 Developer Tools Software
10 .com Domains Domains
11 .net Domains Domains
12 .org Domains Domains
13 Online Games Games
14 PC Games Games
15 PS Games Games
16 RapidShare Accounts Accounts
17 4shared Account Accounts
18 Web Templates Others
19 Flash Intros Others
20 Firewall Security Software
21 Antivirus Security Software
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你需要两次加入桌面
SELECT c1.Id, c1.Name as parentname , c2.name
FROM categories c1
JOIN categories c2
ON c1.id = c2.parentid
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结果将是:
ID ParentName Name
1 software security software
1 software operating software
2 domains .com domains
2 domains .net domains
2 domains .org domains
3 games pc games
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它将为您提供子类别或子类的parentID,parentName和Name.
如果需要,您还可以将其更改为包含子类别ID.
根据您的编辑,您可以使用以下内容:
create table categories
(
id int,
name varchar(50),
parentid int
)
insert into categories values(1, 'software', null)
insert into categories values(2, 'domains', null)
insert into categories values(3, 'games', null)
insert into categories values(6, 'security software', 1)
insert into categories values(7, 'operating systems', 1)
insert into categories values(8, 'browsers', 1)
insert into categories values(10, '.com domains', 2)
insert into categories values(11, '.net domains', 2)
insert into categories values(12, '.org domains', 2)
insert into categories values(13, 'online games', 3)
insert into categories values(14, 'pc games', 3)
insert into categories values(15, 'ps games', 3)
select c1.id
, c1.name
, (select name from categories where c1.parentid = categories.id) as ParentId
from categories c1
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这将导致:
