Dom*_*nik 2 eclipse tomcat web-applications pom.xml maven
假设以下pom.xmlmaven将构建一个client.war文件,当部署到Tomcat时,该文件将具有URLwww.server.com:8080/client/
需要更改什么才能在服务器根目录下访问应用程序www.server.com:8080/?
Run Code Online (Sandbox Code Playgroud)<project> <modelVersion>4.0.0</modelVersion> <groupId>...</groupId> <artifactId>client</artifactId> <packaging>war</packaging> <version>1.0-SNAPSHOT</version> <name>...</name> <url>http://maven.apache.org</url> <build> <resources> <resource> <directory>target/generated-resources</directory> </resource> <resource> <directory>src/main/resources</directory> <filtering>true</filtering> </resource> </resources> <plugins> ... </plugins> <finalName>client</finalName> </build> ... </project>
我相信如果你愿意,你可以离开名为client.war的战争.然后配置tomcat6插件,设置如下路径:
<plugin>
<groupId>org.apache.tomcat.maven</groupId>
<artifactId>tomcat6-maven-plugin</artifactId>
<version>2.0-beta-1</version>
<!-- put the configuration in an execution if you want to... -->
<configuration>
<path>/</path>
<warFile>${project.build.directory}/client.war</warFile>
<!-- other config options here -->
</configuration>
</plugin>
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我没有使用tomcat7版本的插件,但我猜它是类似的.
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