Java splitting input

Question

i'm trying to write a simple code for my project if user types

walk 10

i need to use "walk" command in my walk(distance) method as distance = 10 i have something like that

while (!quit) {
Scanner in = new Scanner(System.in);
String input = in.nextLine();
// if (walk x is typed) {
walk(x);
}
}

i'm using java.util.scanner and another problem is that my method walk(int x) uses int so i need to convert String input to int

i searched the web for a while but couldnt find what i'm looking for (or i didnt understand it)

so anyway i'd appreciate if you can help me thanks

非常感谢所有的答案我的最初的问题是修复但现在我有另一个问题, 当我键入只是"步行"它得到数组超出界限当然因为它试图将null转换为int(不可能)我试过这个并在线检查

                    try {
                    Integer.parseInt(splitStrings[1]);
                    }
                    catch(NumberFormatException e) {
                    System.out.println("error: " + e);
                    }

仍然没有帮助(我对尝试/捕获不好)所以如果用户类型走路没有距离我需要给出一个错误消息再次感谢

好吧,我得到它也只是使用一个简单的事情

            if ("walk".equals(splitStrings[0])) {
                if (splitStrings.length == 2) {
                int distance = Integer.parseInt(splitStrings[1]);
                Robot.walk(distance);
                }
                if (splitStrings.length != 2) {
                    System.out.println("Entry must be like walk 10");
                }
            }

Answer 1

您可以在空间上拆分,在这种情况下,数字将是结果数组的第二个元素(索引1),例如

编辑Adam Liss的以下评论

Integer x = Integer.parseInt(input.split(" ")[1])

Answer 2

尝试对字符串使用split()方法.它将返回一个字符串数组.例如

String s = 'walk 10';
String[] splitStrings = s.split(" ")

现在,要访问10,您可以这样做:

String distanceToWalk = splitStrings[1]

要将其转换为int,请在Integer上使用parseInt()方法

Integer.parseInt(distanceToWalk);

看到

1. http://docs.oracle.com/javase/6/docs/api/java/lang/String.html#split%28java.lang.String%29
2. http://docs.oracle.com/javase/6/docs/api/java/lang/Integer.html#parseInt%28java.lang.String%29