use*_*861 0 html javascript php validation
我正在尝试使用javascript进行表单验证.如果发现错误,javascript应该停止将表单发送到服务器.
我通过编写语句确保javascript返回false:return false;
并且表单仍然发送到服务器.
脚本标签:
<script language="javascript" src="validations.js" type="text/javascript"></script>
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我的表格标签:
FORM id="frm" name="newCustomer" METHOD="POST" ACTION="register.php" onsubmit="return validateNewCustomer()">
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JavaScript函数:
function validateNewCustomer() {
var name = document.getElementById('f_name').value;
var okCustomer = true;
if (name.value == "") {
document.getElementById('f_name').value="kossetak";
document.getElementById('errfname').innerHTML = "Error Name";
okCustomer = false;
} else {
document.getElementById('errname').innerHTML = "";
okCustomer = true;
}
return okCustomer;
}
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我感谢您的帮助.谢谢.
总是从函数返回true,因为name.value == ""它总是false,所以你输入else子句.
请注意,您已经拥有.value此行:
var name = document.getElementById('f_name').value
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所以,当你说name.value你正在访问document.getElementById('f_name').value.value,这将是undefined.