Yai*_*vet 9 model-view-controller asp.net-mvc action-filter asp.net-mvc-3
我在MVC 3中使用Action Filter.
我的问题是,我是否可以在将模型传递给OnActionExecuting事件中的ActionResult之前制作模型?
我需要更改其中一个属性值.
谢谢,
Dar*_*rov 26
OnActionExecuting
事件中还没有模型.控制器操作返回模型.所以你在OnActionExecuted
活动中有一个模特.这就是你可以改变价值观的地方.例如,如果我们假设您的控制器操作返回了一个ViewResult并在其中传递了一些模型,那么您可以如何检索此模型并修改某些属性:
public class MyActionFilterAttribute : ActionFilterAttribute
{
public override void OnActionExecuted(ActionExecutedContext filterContext)
{
var result = filterContext.Result as ViewResultBase;
if (result == null)
{
// The controller action didn't return a view result
// => no need to continue any further
return;
}
var model = result.Model as MyViewModel;
if (model == null)
{
// there's no model or the model was not of the expected type
// => no need to continue any further
return;
}
// modify some property value
model.Foo = "bar";
}
}
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如果要修改作为操作参数传递的视图模型的某些属性的值,那么我建议在自定义模型绑定器中执行此操作.但在OnActionExecuting
事件中也可以实现这一目标:
public class MyActionFilterAttribute : ActionFilterAttribute
{
public override void OnActionExecuting(ActionExecutingContext filterContext)
{
var model = filterContext.ActionParameters["model"] as MyViewModel;
if (model == null)
{
// The action didn't have an argument called "model" or this argument
// wasn't of the expected type => no need to continue any further
return;
}
// modify some property value
model.Foo = "bar";
}
}
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