kd7*_*iwp 146 c# dictionary
有没有人知道我创建它时是否可以将值插入C#Dictionary?dict.Add(int, "string")
如果有更高效的东西,我可以,但不想,为每个项目做
:
Dictionary<int, string>(){(0, "string"),(1,"string2"),(2,"string3")};
Run Code Online (Sandbox Code Playgroud)
Dan*_*ker 192
这里有关于如何做到这一点的整个页面:
http://msdn.microsoft.com/en-us/library/bb531208.aspx
例:
在下面的代码示例中,使用
Dictionary<TKey, TValue>
类型的实例初始化aStudentName
:
var students = new Dictionary<int, StudentName>()
{
{ 111, new StudentName {FirstName="Sachin", LastName="Karnik", ID=211}},
{ 112, new StudentName {FirstName="Dina", LastName="Salimzianova", ID=317}},
{ 113, new StudentName {FirstName="Andy", LastName="Ruth", ID=198}}
};
Run Code Online (Sandbox Code Playgroud)
Tim*_*ter 45
Dictionary<int, string> dictionary = new Dictionary<int, string> {
{ 0, "string" },
{ 1, "string2" },
{ 2, "string3" } };
Run Code Online (Sandbox Code Playgroud)
Hen*_*man 12
你几乎在那里:
var dict = new Dictionary<int, string>()
{ {0, "string"}, {1,"string2"},{2,"string3"}};
Run Code Online (Sandbox Code Playgroud)
mat*_*die 10
您还可以使用Lambda表达式从任何其他IEnumerable对象插入任何键值对.键和值可以是您想要的任何类型.
Dictionary<int, string> newDictionary =
SomeList.ToDictionary(k => k.ID, v => v.Name);
Run Code Online (Sandbox Code Playgroud)
我发现这更简单,因为你在.NET中使用IEnumerable对象
希望有所帮助!
泰德.
您可以实例化字典并将项目添加到其中,如下所示:
var dictionary = new Dictionary<int, string>
{
{0, "string"},
{1, "string2"},
{2, "string3"}
};
Run Code Online (Sandbox Code Playgroud)
就像你知道C#6一样,你现在可以按如下方式初始化它
var students = new Dictionary<int, StudentName>()
{
[111] = new StudentName {FirstName="Sachin", LastName="Karnik", ID=211},
[112] = new StudentName {FirstName="Dina", LastName="Salimzianova", ID=317},
[113] = new StudentName {FirstName="Andy", LastName="Ruth", ID=198}
};
Run Code Online (Sandbox Code Playgroud)
更干净:)