use*_*043 4 android ksoap2 android-asynctask
我正在编写一个主要使用从Web服务获取的数据的应用程序,我想使用AsyncTask在后台运行SOAP调用...我对Android很新(作为iOS程序员),所以我'这个有点新......
现在,我有一个登录屏幕,在那里我使用用户提供的登录信息并根据服务器上的信息进行检查...
所以在我的登录活动中:
loginBtn.setOnClickListener(new OnClickListener()
{
public void onClick(View v)
{
//Run the connection to authenticate the user
AuthenticateConnection mAuth = new AuthenticateConnection();
mAuth.mNumber = number;
mAuth.mPassword = pass;
mAuth.connection();
}
}
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我的肥皂课是这样的:
public class AuthenticateConnection
{
private static final String SOAP_ACTION = "http://tempuri.org/Authenticate";
private static final String METHOD_NAME = "Authenticate";
private static final String NAMESPACE = "http://tempuri.org/";
private String URL;
public Boolean userOK;
public String mNumber;
public String mPassword;
public AuthenticateConnection()
{
}
public void connection()
{
Singleton service = Singleton.getInstance();
String firstURL = service.getURL();
URL = firstURL + "Parent.svc";
System.out.println("Connection to: " + URL);
//Initialize soap request
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
//Add parameters
request.addProperty("login", mNumber);
request.addProperty("password", mPassword);
//Declare the version of the SOAP request
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.dotNet=true;
envelope.implicitTypes=true;
envelope.setAddAdornments(false);
//Prepare request
envelope.setOutputSoapObject(request);
//Needed to make the internet call
HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
//Allow for debugging - needed to output the request
androidHttpTransport.debug = true;
try
{
//this is the actual part that will call the web service
androidHttpTransport.call(SOAP_ACTION, envelope);
//Get the SoapResult from the envelope body.
//Object result = envelope.getResponse();
//Object result = envelope.bodyIn;
SoapObject sResult = (SoapObject)envelope.bodyIn;
String tempID = sResult.getProperty("AuthenticateResult").toString();
//Check if the user exists and has the correct password
if(tempID != "-1")
{
userOK = true;
//Store the values in the singleton class
service.parentID = sResult.getProperty("AuthenticateResult").toString();
service.parentToken = sResult.getProperty("token").toString();
}
//If -1 is returned, then either the number or the password is incorrect
else
{
userOK = false;
}
} catch(org.xmlpull.v1.XmlPullParserException ex2)
{
//System.out.println(androidHttpTransport.requestDump.toString());
} catch (Exception e)
{
e.printStackTrace();
System.out.println(androidHttpTransport.requestDump.toString());
}
}
}
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所以我的问题是,我如何使用AsyncTask执行此操作?我一直在寻找关于AsyncTask的一些教程,但到目前为止还没有真正"得到它"......
你可以做:
private class ConnectionTask extends AsyncTask<String, Void, Void> {
private ProgressDialog dialog = new ProgressDialog(ACTIVITY_NAME.this);
protected void onPreExecute() {
dialog.setMessage("Connecting...");
dialog.show();
}
protected void doInBackground(String... args) {
AuthenticateConnection mAuth = new AuthenticateConnection();
mAuth.mNumber = args[0];
mAuth.mPassword = args[1];
mAuth.connection();
}
protected void onPostExecute(Void v) {
if (dialog.isShowing()) {
dialog.dismiss();
}
}
}
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然后叫它:
loginBtn.setOnClickListener(new OnClickListener()
{
public void onClick(View v)
{
//Run the connection to authenticate the user
new ConnectionTask().execute(number, pass);
}
}
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您的connection方法AuthenticateConnection应该返回一些内容以确保用户已经过身份验证.然后你可以使用这个值onPostExecute,如下所示:
protected void onPostExecute(Integer res) {
if (dialog.isShowing()) {
dialog.dismiss();
}
if (res.intValue() == OK) {
/* Maybe start a new Activity ...*/
} else {
/* Maybe show a Toast with an error message ...*/
}
}
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在这种情况下,asynctask的签名将会改变:
private class ConnectionTask extends AsyncTask<String, Void, Integer>
doInBackground应该返回一个Integer.
希望能帮助到你.
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