使用编程排序绑定到DataGridView的可排序BindingList

Question

我已经在http://msdn.microsoft.com/en-us/library/aa480736.aspx上实现了SortableSearchableList类,并为它添加了一个Sort方法,如下所示:

public void Sort(PropertyDescriptor prop, ListSortDirection direction)
{
ApplySortCore(prop, direction);
}

这个类在通过单击任何列标题对DataGridView进行排序时起作用,但是我需要能够以编程方式调用指定列的Sort方法(在本例中使用sortButton控件).我在网上找到的几个代码示例建议获取列的PropertyDescriptor并将其传递给ApplySortCore方法.我还没有那个工作.我可以获取DataGridView或SortableSearchableList的PropertyDescriptorCollection属性,但似乎无法获取Find方法来获取指定列/成员的PropertyDescriptor.这是我的其余代码:

namespace SortableBindingListTest
{
public partial class Form1 : Form
{
    private SortableSearchableList<Tags> alarms = new SortableSearchableList<Tags>();
    public Form1()
    {
        InitializeComponent();
        alarms.Add(new Tags("some text", "1"));
        alarms.Add(new Tags("more text", "2"));
        alarms.Add(new Tags("another one", "3"));
        dataGridView1.AutoGenerateColumns = false;
        dataGridView1.AllowUserToAddRows = true;
        dataGridView1.EditMode = DataGridViewEditMode.EditOnEnter;
        dataGridView1.RowHeadersVisible = false;
        dataGridView1.AutoSizeColumnsMode = System.Windows.Forms.DataGridViewAutoSizeColumnsMode.Fill;
        DataGridViewTextBoxColumn alarmColumn = new DataGridViewTextBoxColumn();
        alarmColumn.DataPropertyName = "Alarm";
        alarmColumn.Name = "Alarm";
        alarmColumn.HeaderText = "Alarm";
        DataGridViewTextBoxColumn messageColumn = new DataGridViewTextBoxColumn();
        messageColumn.DataPropertyName = "Message";
        messageColumn.Name = "Message";
        messageColumn.HeaderText = "Message";
        dataGridView1.Columns.Add(alarmColumn);
        dataGridView1.Columns.Add(messageColumn);
        dataGridView1.DataSource = alarms;
    }

    private void sortButton_Click(object sender, EventArgs e)
    {
        // try getting properties of BindingList
        PropertyDescriptorCollection listProperties = TypeDescriptor.GetProperties(alarms);
        PropertyDescriptor alarmProp = listProperties.Find("Alarm", false);
        // prop is null at this point, so the next line fails
        alarms.Sort(alarmProp, ListSortDirection.Ascending);
        // try getting properties of DataGridView column
        PropertyDescriptorCollection dgvProperties = TypeDescriptor.GetProperties(dataGridView1);
        PropertyDescriptor columnProp = dgvProperties.Find("Alarm", false);
        // columnProp is null at this point, so the next line also fails
        alarms.Sort(columnProp, ListSortDirection.Ascending);
    }
}

public class Tags : INotifyPropertyChanged
{
    private string _alarm;
    private string _message;
    public event PropertyChangedEventHandler PropertyChanged;
    public Tags(string alarm, string message)
    {
        _alarm = alarm;
        _message = message;
    }

    public string Alarm
    {
        get { return _alarm; }
        set
        {
            _alarm = value;
            this.NotifyPropertyChanged("Alarm");
        }
    }
    public string Message
    {
        get { return _message; }
        set
        {
            _message = value;
            this.NotifyPropertyChanged("Message");
        }
    }
    private void NotifyPropertyChanged(string name)
    {
        if (PropertyChanged != null)
            PropertyChanged(this, new PropertyChangedEventArgs(name));
    }
}
}

任何帮助将不胜感激.

Answer 1

试试这个

dataGridView1.Sort(dataGridView.Columns[0],ListSortDirection.Ascending);