如何从Oracle中的值列表中进行选择

Question

我指的是这个stackoverflow答案:

如何从SQL Server中的值列表中进行选择

如何在Oracle中完成类似的工作？

我已经在这个页面上看到了其他使用的答案UNION,虽然这种方法在技术上有效,但它并不是我想在我的情况下使用的.

所以我希望保持语法或多或少看起来像逗号分隔的值列表.

关于create type table 答案的更新:

我有一张桌子:

CREATE TABLE "BOOK" 
(   "BOOK_ID" NUMBER(38,0)
)

我使用此脚本,但它不会向BOOK表中插入任何行:

create type number_tab is table of number;

INSERT INTO BOOK (
    BOOK_ID
)
SELECT A.NOTEBOOK_ID FROM
    (select column_value AS NOTEBOOK_ID from table (number_tab(1,2,3,4,5,6))) A
;

脚本输出:

TYPE number_tab compiled
Warning: execution completed with warning

但是,如果我使用此脚本,它会向BOOK表中插入新行:

INSERT INTO BOOK (
    BOOK_ID
)
SELECT A.NOTEBOOK_ID FROM
    (SELECT (LEVEL-1)+1 AS NOTEBOOK_ID FROM DUAL CONNECT BY LEVEL<=6) A
;

Answer 1

您无需创建任何存储类型,您可以评估Oracle的内置集合类型.

select distinct column_value from table(sys.odcinumberlist(1,1,2,3,3,4,4,5))

Answer 2

如果您要转换以逗号分隔的值列表:

select column_value 
from table(sys.dbms_debug_vc2coll('One', 'Two', 'Three', 'Four'));

-- Or

select column_value 
from table(sys.dbms_debug_vc2coll(1,2,3,4));

如果你想转换一串逗号分隔值,那么我会推荐Justin Cave的正则表达式SQL解决方案.

Answer 3

从Oracle 12.2开始，不需要该TABLE函数，直接从内置集合中选择即可。

SQL> select * FROM sys.odcinumberlist(5,2,6,3,78);

COLUMN_VALUE
------------
           5
           2
           6
           3
          78

SQL> select * FROM sys.odcivarchar2list('A','B','C','D');

COLUMN_VALUE
------------
A
B
C
D

Answer 4

你可以这样做：

create type number_tab is table of number;

select * from table (number_tab(1,2,3,4,5,6));

该列由 Oracle 命名为 COLUMN_VALUE，因此这也适用：

select column_value from table (number_tab(1,2,3,4,5,6));

Answer 5

有多种方法可以采用逗号分隔列表并将其解析为多行数据.在SQL中

SQL> ed
Wrote file afiedt.buf

  1  with x as (
  2    select '1,2,3,a,b,c,d' str from dual
  3  )
  4   select regexp_substr(str,'[^,]+',1,level) element
  5     from x
  6* connect by level <= length(regexp_replace(str,'[^,]+')) + 1
SQL> /

ELEMENT
----------------------------------------------------
1
2
3
a
b
c
d

7 rows selected.

或者在PL/SQL中

SQL> create type str_tbl is table of varchar2(100);
  2  /

Type created.

SQL> create or replace function parse_list( p_list in varchar2 )
  2    return str_tbl
  3    pipelined
  4  is
  5  begin
  6    for x in (select regexp_substr( p_list, '[^,]', 1, level ) element
  7                from dual
  8             connect by level <= length( regexp_replace( p_list, '[^,]+')) + 1)
  9    loop
 10      pipe row( x.element );
 11    end loop
 12    return;
 13  end;
 14
 15  /

Function created.

SQL> select *
  2    from table( parse_list( 'a,b,c,1,2,3,d,e,foo' ));

COLUMN_VALUE
--------------------------------------------------------------------------------
a
b
c
1
2
3
d
e
f

9 rows selected.