在Symfony 2中使用简单bundle类中的容器

vin*_*nux 4 php symfony

我在Symfony 2中的bundle中创建了一个简单的类:

class MyTest {
    public function myFunction() {
        $logger = $this->get('logger');
        $logger->err('testing out');
    }
}
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我怎样才能访问容器?

JF *_*mon 13

您需要注入服务容器.你的课将看起来像这样:

use Symfony\Component\DependencyInjection\ContainerInterface;

class MyTest
{
    private $container;

    public function __construct(ContainerInterface $container)
    {
        $this->container = $container;
    }

    public function myFunction()
    {
        $logger = $this->container->get('logger');
        $logger->err('testing out');
    }
}
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然后在控制器或ContainerAware实例中:

$myinstance = new MyTest($this->container);
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如果您需要更多解释:http://symfony.com/doc/current/book/service_container.html


Eln*_*mov 7

在大多数情况下,注入整个容器是个坏主意.单独注入所需的服务.

namespace Vendor;

use Symfony\Component\HttpKernel\Log\LoggerInterface;

class MyTest 
{
    private $logger;

    public function __construct(LoggerInterface $logger) 
    {
        $this->logger = $logger;
    }

    public function myFunction() 
    {
        $logger->err('testing out');
    }
}
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注册服务services.yml:

services:
    my_test:
        class: Vendor\MyTest
        arguments: [@logger]
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