Mon*_*cho 2 sql-server informix
将以下Transact-SQL代码转录到Informix Dynamic Server(IDS)9.40的最佳方法是什么:
目标:我需要前50个订单及其各自的订单行
select *
from (select top 50 * from orders) a inner join lines b
on a.idOrder = b.idOrder
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我的问题在于subselect,因为Informix不允许subselect中的FIRST选项.
有什么简单的想法吗?
官方答案是"请从IDS 9.40升级,因为它不再受IBM支持".也就是说,IDS 9.40不是当前版本 - 并且应该(理想情况下)不使用.
使用IDS 11.50,我可以写:
SELECT *
FROM (SELECT FIRST 10 * FROM elements) AS e
INNER JOIN compound_component AS a
ON e.symbol = a.element
INNER JOIN compound AS c
ON c.compound_id = a.compound_id
;
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这或多或少等同于您的查询.因此,如果使用当前版本的IDS,则可以使用与Transact-SQL中几乎相同的表示法编写查询(使用FIRST代替TOP).
你能在IDS 9.40做什么?请原谅......我必须运行我的IDS 9.40.xC7服务器(此修订包于2005年发布;原始版本可能在2003年末)...
第一个问题 - IDS 9.40不允许FROM子句中的子查询.
第二个问题 - IDS 9.40不允许在以下任何一种情况下使用"FIRST n"表示法:
SELECT FIRST 10 * FROM elements INTO TEMP e;
INSERT INTO e SELECT FIRST 10 * FROM elements;
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第三个问题 - IDS 9.40没有简单的ROWNUM.
因此,要解决这些问题,我们可以编写(使用临时表 - 稍后我们将删除它):
SELECT e1.*
FROM elements AS e1, elements AS e2
WHERE e1.atomic_number >= e2.atomic_number
GROUP BY e1.atomic_number, e1.symbol, e1.name, e1.atomic_weight, e1.stable
HAVING COUNT(*) <= 10
INTO TEMP e;
SELECT *
FROM e INNER JOIN compound_component AS a
ON e.symbol = a.element
INNER JOIN compound AS c
ON c.compound_id = a.compound_id;
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这与IDS 11.50中的单个查询产生相同的答案.我们可以避开临时表吗?是的,但它更详细:
SELECT e1.*, a.*, c.*
FROM elements AS e1, elements AS e2, compound_component AS a,
compound AS c
WHERE e1.atomic_number >= e2.atomic_number
AND e1.symbol = a.element
AND c.compound_id = a.compound_id
GROUP BY e1.atomic_number, e1.symbol, e1.name, e1.atomic_weight,
e1.stable, a.compound_id, a.element, a.seq_num,
a.multiplicity, c.compound_id, c.name
HAVING COUNT(*) <= 10;
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将其应用于原始订单加订单行示例留给读者练习.
"元素表"的相关模式子集:
-- See: http://www.webelements.com/ for elements.
-- See: http://ie.lbl.gov/education/isotopes.htm for isotopes.
CREATE TABLE elements
(
atomic_number INTEGER NOT NULL UNIQUE CONSTRAINT c1_elements
CHECK (atomic_number > 0 AND atomic_number < 120),
symbol CHAR(3) NOT NULL UNIQUE CONSTRAINT c2_elements,
name CHAR(20) NOT NULL UNIQUE CONSTRAINT c3_elements,
atomic_weight DECIMAL(8,4) NOT NULL,
stable CHAR(1) DEFAULT 'Y' NOT NULL
CHECK (stable IN ('Y', 'N'))
);
CREATE TABLE compound
(
compound_id SERIAL NOT NULL PRIMARY KEY,
name VARCHAR(100) NOT NULL UNIQUE
);
-- The sequence number is used to order the components within a compound.
CREATE TABLE compound_component
(
compound_id INTEGER REFERENCES compound,
element CHAR(3) NOT NULL REFERENCES elements(symbol),
seq_num SMALLINT DEFAULT 1 NOT NULL
CHECK (seq_num > 0 AND seq_num < 20),
multiplicity INTEGER NOT NULL
CHECK (multiplicity > 0 AND multiplicity < 20),
PRIMARY KEY(compound_id, seq_num)
);
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输出(在我的示例数据库中):
1 H Hydrogen 1.0079 Y 1 H 1 2 1 water
1 H Hydrogen 1.0079 Y 3 H 2 4 3 methane
1 H Hydrogen 1.0079 Y 4 H 2 6 4 ethane
1 H Hydrogen 1.0079 Y 5 H 2 8 5 propane
1 H Hydrogen 1.0079 Y 6 H 2 10 6 butane
1 H Hydrogen 1.0079 Y 11 H 2 5 11 ethanol
1 H Hydrogen 1.0079 Y 11 H 4 1 11 ethanol
6 C Carbon 12.0110 Y 2 C 1 1 2 carbon dioxide
6 C Carbon 12.0110 Y 3 C 1 1 3 methane
6 C Carbon 12.0110 Y 4 C 1 2 4 ethane
6 C Carbon 12.0110 Y 5 C 1 3 5 propane
6 C Carbon 12.0110 Y 6 C 1 4 6 butane
6 C Carbon 12.0110 Y 7 C 1 1 7 carbon monoxide
6 C Carbon 12.0110 Y 9 C 2 1 9 magnesium carbonate
6 C Carbon 12.0110 Y 10 C 2 1 10 sodium bicarbonate
6 C Carbon 12.0110 Y 11 C 1 2 11 ethanol
8 O Oxygen 15.9990 Y 1 O 2 1 1 water
8 O Oxygen 15.9990 Y 2 O 2 2 2 carbon dioxide
8 O Oxygen 15.9990 Y 7 O 2 1 7 carbon monoxide
8 O Oxygen 15.9990 Y 9 O 3 3 9 magnesium carbonate
8 O Oxygen 15.9990 Y 10 O 3 3 10 sodium bicarbonate
8 O Oxygen 15.9990 Y 11 O 3 1 11 ethanol
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