Nie*_*ein 1 sql sqlite performance max min
我有一个SQL查询,我检查一个值是否在表的最大值和最小值之间.我现在实现如下:
SELECT spectrum_id, feature_table_id
FROM 'spectrum', 'feature'
WHERE `spectrum`.msrun_msrun_id = 1
AND `feature`.msrun_msrun_id = 1
AND (SELECT min(rt) FROM `convexhull` WHERE `convexhull`.feature_feature_table_id = `feature`.feature_table_id) <= scan_start_time
AND scan_start_time <= (SELECT max(rt) FROM `convexhull` WHERE 'convexhull'.feature_feature_table_id = 'feature'.feature_table_id)
AND (SELECT min(mz) FROM `convexhull` WHERE `convexhull`.feature_feature_table_id = `feature`.feature_table_id) <= base_peak_mz
AND base_peak_mz <= (SELECT max(mz) FROM `convexhull` WHERE `convexhull`.feature_feature_table_id = `feature`feature_table_id)
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这运行得非常慢,因为每次运行此查询时我都会从convexhull中选择4次,所以我尝试使用内部连接来改进它:
SELECT spectrum_id, feature_table_id
FROM 'spectrum', 'feature'
INNER JOIN `convexhull` ON `convexhull`.feature_feature_table_id = `feature`.feature_table_id
WHERE `spectrum`.msrun_msrun_id = ? "+
AND `feature`.msrun_msrun_id = ? "+
AND min(`convexhull`.rt) <= scan_start_time "+
AND scan_start_time <= max(`convexhull`.rt) "+
AND min(`convexhull`.mz) <= base_peak_mz "+
AND base_peak_mz <= max(`convexhull`.mz)", spectrumFeature_InputValues)
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但是,min()和max()语句只能在select语句之后使用.如何让第一个查询更有效率,这样我就可以获得min和max rt和mz而无需进行4次查询?
小智 6
编辑:再多花几分钟再看一遍,并意识到所有数据来自那一张桌子,所以这样的事情应该有效
SELECT
spectrum_id
,feature_table_id
FROM
spectrum AS s
INNER JOIN feature AS f
on f.msrun_msrun_id = s.msrun_msrun_id
INNER JOIN (select
feature_feature_table_id
,min(rt) AS rtMin
,max(rt) AS rtMax
,min(mz) AS mzMin
,max(mz) as mzMax
FROM
convexhull
GROUP BY
feature_feature_table_id
) AS t
ON t.feature_feature_table_id = f.feature_table_id
WHERE
s.msrun_msrun_id = 1
AND s.scan_start_time >= t.rtMin
AND s.scan_start_time <= t.rtMax
AND base_peak_mz >= t.mxMin
AND base_peak_mz <= t.mzMax
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我想你想通过feature_feature_table_id从凸包表和组中进行选择,以获得该分组中的最小和最大rt.
然后你可以用括号中的select选择它给它一个名字(如t)并加入它.
希望这是让你上路...如果不在这里创建一个示例模式:http://sqlfiddle.com/
并提入您的查询,我可以修改它.
作为旁注,我想你想在特定字段上加入这些表,而不是从where子句中选择比较:
SELECT spectrum_id, feature_table_id
FROM 'spectrum', 'feature'
WHERE `spectrum`.msrun_msrun_id = 1
AND `feature`.msrun_msrun_id = 1
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和:
SELECT
spectrum_id
,feature_table_id
FROM
spectrum AS s
INNER JOIN feature AS f
on f.msrun_msrun_id = s.msrun_msrun_id
WHERE
s.msrun_msrun_id = 1
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如果我有什么问题,请告诉我.