故事板Xcode中的UISearchBar

Question

我想在storyboard xcode中为我的表创建searchBar,Everythings适合我,我没有任何错误,只是搜索不起作用.

我看到了这两个教程,但仍然无效.我无法搜索.我的教程:

   -http://stackoverflow.com/questions/9897171/uisearchbar-implemented-with-storyboards
   -http://www.youtube.com/watch?v=IqDZHgI_s24

你能帮帮我吗,先谢谢你!

这是我的代码

CreateViewController.h

#import <UIKit/UIKit.h>

@interface CreateViewController : UITableViewController <UITableViewDelegate, UITableViewDataSource,       UISearchBarDelegate>
{
// @property (weak, nonatomic) IBOutlet UISearchBar *searchBar;
NSArray *datas;
NSMutableArray *displayItems;
IBOutlet UITableView * tableView;
IBOutlet UISearchBar * searchbar;
}

@end

CreateViewController.m

#import "CreateViewController.h"

@interface CreateViewController ()

@end

@implementation CreateViewController

- (id)initWithStyle:(UITableViewStyle)style
{
self = [super initWithStyle:style];
if (self) {
    // Custom initialization
}
return self;
}

- (void)viewDidLoad
{
[super viewDidLoad];

datas = [NSMutableArray arrayWithObjects:@"Johan", @"Paul",@"George",@"Ringo", nil];
displayItems = [[NSMutableArray alloc] initWithArray:datas];
[super viewDidLoad];
}

- (void)viewDidUnload
{
[super viewDidUnload];
// Release any retained subviews of the main view.
// e.g. self.myOutlet = nil;
}

- (BOOL)shouldAutorotateToInterfaceOrientation:(UIInterfaceOrientation)interfaceOrientation
{
return (interfaceOrientation == UIInterfaceOrientationPortrait);
}

#pragma mark - Table view data source

- (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView
{
// Return the number of sections.
return 1;
}

 - (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section
{
// Return the number of rows in the section.
return [datas count];
}

- (UITableViewCell *)tableView:(UITableView *)atableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
static NSString *CellIdentifier = @"Cell";//This is the identifier in storyboard    
UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier];
if(!cell) {
    cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:@"Cell"];
}

cell.textLabel.text = [datas objectAtIndex:indexPath.row];
return cell;
}
-(void)searchbar:(UISearchBar *)searchbar textDidChange:(NSString *)searchText{
if([searchText length] == 0){
    [displayItems removeAllObjects];
    [displayItems addObjectsFromArray:datas];
}else{
    [displayItems removeAllObjects];
    for(NSString * string in datas){
        NSRange r = [string rangeOfString:searchText options:NSCaseInsensitiveSearch];
        if (r.location != NSNotFound){
            [displayItems addObject:string];   
        }
    }
}
[tableView reloadData];
}

 #pragma mark - Table view delegate

 - (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath
 {
// Navigation logic may go here. Create and push another view controller.
/*
 <#DetailViewController#> *detailViewController = [[<#DetailViewController#> alloc] initWithNibName:@"<#Nib    name#>" bundle:nil];
 // ...
 // Pass the selected object to the new view controller.
 [self.navigationController pushViewController:detailViewController animated:YES];
 */
}

@end

Answer 1

使用本教程iOS快速提示:使用搜索栏过滤UITableView

http://code-ninja.org/blog/2012/01/08/ios-quick-tip-filtering-a-uitableview-with-a-search-bar/

-(void)searchBar:(UISearchBar*)searchBar textDidChange:(NSString*)text
{
if(text.length == 0)
{
    isFiltered = FALSE;
}
else
{
    isFiltered = true;
    filteredTableData = [[NSMutableArray alloc] init];

    for (Food* food in allTableData)
    {
        NSRange nameRange = [food.name rangeOfString:text options:NSCaseInsensitiveSearch];
        NSRange descriptionRange = [food.description rangeOfString:text options:NSCaseInsensitiveSearch];
        if(nameRange.location != NSNotFound || descriptionRange.location != NSNotFound)
        {
            [filteredTableData addObject:food];
        }
    }
}

[self.tableView reloadData];
}

Answer 2

像这样做，

• 在你的头文件中声明这样的数组，

  NSMutableArray *datas;
  NSMutableArray *displayItems;
  

• 然后像这样改变viewDidLoad中的数组初始化，

  datas = [[NSMutableArray alloc] initWithObjects:@"Johan", @"Paul",@"George",@"Ringo", nil];
  displayItems = [[NSMutableArray alloc] initWithArray:datas];
  

• 更改cellForRowAt方法中的数组，

  cell.textLabel.text = [displayItems objectAtIndex:indexPath.row];
  

• 然后使用 NSLog 在textDidChange方法中打印您的搜索字符串。如果没有打印，则 IBOutlet 连接有问题。如果打印出来，请替换此方法并查看是否有效，

  -(void)searchbar:(UISearchBar *)searchbar textDidChange:(NSString *)searchText{
  
  if([searchText length] == 0){
  
  }else{
      [displayItems removeAllObjects];
      for (int i=0; i<[datas count]; i++) {
          if ([searchText hasPrefix:[datas objectAtIndex:i]]) {
              [displayItems addObject:[datas objectAtIndex:i]];
          } else {
  
          }
      }
  }
  [tableView reloadData];
  }
  

我的排序方法不是世界上最好的。但请尝试让您的代码正常工作。

编辑：我认为你的代表不会解雇。尝试这个方法而不是上面的方法。

- (void) searchBarSearchButtonClicked:(UISearchBar*) theSearchBar
{
if([searchBar.text length] == 0){
arrayDisplayData = arrayOriginalData;
}else{
    [arrayDisplayData removeAllObjects];
    for(NSString * string in arrayOriginalData){
        NSRange r = [string rangeOfString:searchBar.text options:NSCaseInsensitiveSearch];
        if (r.location != NSNotFound){
            [arrayDisplayData addObject:string];   
        }
    }
}
[tblResults reloadData];
}

或这个，

- (BOOL)searchBar:(UISearchBar *)searchBar shouldChangeTextInRange:(NSRange)range replacementText:(NSString *)text