Edw*_*uay 2 c# linq stringbuilder
在我的应用程序中,我使用StringBuilder使用此代码构建XML文件:
StringBuilder sb = new StringBuilder();
sb.Append("<?xml version=\"1.0\" encoding=\"utf-8\"?>" + Environment.NewLine);
sb.Append(String.Format("<{0}>{1}", _pluralCamelNotation, Environment.NewLine));
for (int index = 0; index < 3; index++)
{
sb.Append(String.Format("\t<{0}>{1}", _singularCamelNotation, Environment.NewLine));
foreach (DataType dataType in _allDataTypes)
{
sb.Append(String.Format("\t\t<{0}>{2}</{0}>{1}", dataType.CamelCaseNotation, Environment.NewLine, dataType.GetDummyData()));
}
sb.Append(String.Format("\t</{0}>{1}", _singularCamelNotation, Environment.NewLine));
}
sb.Append(String.Format("</{0}>{1}", _pluralCamelNotation, Environment.NewLine));
return sb.ToString();
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如何使用LINQ执行相同的操作,如下所示:
PSEUDO-CODE:
var xdoc = new XDocument(
new XDeclaration("1.0", "utf-8", null),
for (int index = 0; index < 3; index++) {
new XElement(_pluralCamelNotation,
_allDataTypes.Select(datatype => new XElement(_singularCamelNotation,
new XElement(datatype.CamelCaseNotation, datatype.GetDummyData())
))
)
}
);
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Mar*_*ell 11
即使没有LINQ,也不应该通过连接XmlWriter来编写xml ... 这样会很合适:
XmlWriterSettings settings = new XmlWriterSettings();
settings.NewLineHandling = NewLineHandling.Entitize;
settings.Indent = true;
settings.IndentChars = "\t";
StringBuilder sb = new StringBuilder();
using (XmlWriter xw = XmlWriter.Create(sb, settings))
{
xw.WriteStartDocument();
xw.WriteStartElement(_pluralCamelNotation);
for (int i = 0; i < 3; i++)
{
xw.WriteStartElement(_singularCamelNotation);
foreach (DataType dataType in _allDataTypes)
{
xw.WriteElementString(dataType.ToString(),
dataType.GetDummyData());
}
xw.WriteEndElement();
}
xw.WriteEndElement();
xw.WriteEndDocument();
xw.Close();
}
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您可以XmlWriterSettings用来控制行间距等内容.
或者,使用LINQ-to-XML:
XDocument doc = new XDocument(
new XDeclaration("1.0", null, null),
new XElement(_pluralCamelNotation,
Enumerable.Range(1,3).Select(
i => new XElement(_singularCamelNotation,
_allDataTypes.Select(
dataType => new XElement(
dataType.ToString(),
dataType.GetDummyData())
)
))));
string t = doc.ToString();
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