mau*_*lla 1 php components controller cakephp formhelper
所以我们有各种各样的搜索页面,每个搜索页面都有不同的搜索条件,所以我决定编写一个组件,它将从控制器获取传递给它的参数,收集必要的数据并返回一个数组,我可以将其设置为在我的内部使用查看文件以填充下拉框以过滤条件.
我已经设法将所有内容写到我必须使用cakePHP助手来构建动态选择框的地方.我确信我做错了,如果有更简单的方法可以做到这一点并且仍然保持一些动态,请尽可能协助:
// COMPONENT METHOD:
public function filterQueries($parameters) {
// Get defaults from the user:
$criteria = $parameters["custom"];
$defaults = $parameters["defaults"];
// Validate the defaults the user may want and assign them to the return array:
if($defaults != "false") {
foreach($defaults as $key => $value) {
if(array_key_exists($value, $this->defaults)) {
$this->returnArray["defaults"][$value] = $this->defaults[$value];
}
}
}
// Get all data for the custom requested form fields:
if($criteria != false) {
foreach($criteria as $model => $arguments) {
$fields = $arguments["fields"];
$conditions = $arguments["conditions"];
$recursive = $arguments["recursive"];
if(!in_array($model,$this->uses)) {
$useModel = ClassRegistry::init($model);
} else {
$useModel = $this->$$model;
}
$array = $useModel->find("all",array("conditions" => $conditions, "fields" => $fields, "recursive" => $recursive));
$this->returnArray["custom"][$model] = $array;
}
}
return $this->returnArray;
}
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上面的函数将获得一个数组,该数组分解自定义搜索或默认值(上面没有包括但它都可以工作,它会像我预期的那样返回数组.
// The code within my action to get the content from above:
// Load the Filters component to search data:
$search = $this->Components->load("Filter");
// Tell search what you want:
$searchBoxes = array(
"defaults" => array("statuses", "survey_type"),
"custom" => array(
"User" => array(
"fields" => array("User.id","User.first_name", "User.last_name"),
"conditions" => array("User.user_group_id" => "4f847c63-1840-446e-88be-3e4d29566cf0"),
"recursive" => -1
)
)
);
$filterResults = $search->filterQueries($searchBoxes);
$this->set("filters",$filterResults);
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所以现在我在我的视图文件中得到了这个多关联数组(一切都还好),但我想现在根据上面创建的数组构建一个用户下拉列表示例,但结果与我的预期完全不同:
echo $this->Form->input('user_id',
array(
"type" => "select",
"options" => $filters["custom"]["User"]
)
);
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HTML输出被破坏并显示如下:
<option value="last_name">Doe</option>
<option value="first_name">Jihn</option>
<optgroup label="User"> </optgroup>
<optgroup label="1"> </optgroup>
<option value="last_name">Marilyn</option>
<option value="first_name">Monroe</option>
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我承认我没有很多蛋糕经验,但无法理解如何才能得到结果:
<option value='USERID'>NAME</option> // Yes I know the names and surnames must be concatinated still
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任何建议帮助或如何做的指导,并以正确的方式做,将非常感谢:)
VARDUMP ON $ filters ['custom'] ['users']
array
0 =>
array
'User' =>
array
'id' => string '4f84840e-cda8-4704-8fdf-210729566cf0' (length=36)
'first_name' => string 'Name' (length=4)
'last_name' => string 'Surname' (length=11)
1 =>
array
'User' =>
array
'id' => string '4f8488cb-53e0-4f72-af73-3de229566cf0' (length=36)
'first_name' => string 'Name' (length=6)
'last_name' => string 'Surname' (length=6)
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您可以通过执行以下操作来增强输出:
1)对于组合表的两个字段,可以"virtualfields" 在模型中使用,如下所示:例如,如果您有用户模型,则可以定义如下:
public $virtualFields = array(
'full_name' => 'CONCAT(first_name, " ",last_name)'
);
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所以现在只要调用findUser模型的方法,就会得到"full_name"字段.
2)为了从表中获取选择框的数据,您可以使用该find('list')方法.例如,如果您需要id,full_name (last and first name combined using the virtual fields)表的用户模型,可以按如下方式完成:
$this->User->find('list',array('fields'=>array('id','full_name'),'conditions'=>$conditions))
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我希望这有帮助..