如何在SciPy中创建对角稀疏矩阵

use*_*372 3 python numpy scipy sparse-matrix diagonal

我正在尝试创建一个稀疏矩阵,其中2D图案沿着对角线向下延伸.用一个简单的例子来解释这可能是最容易的.

说我的模式是:[1,0,2,0,1] ......

我想创建一个稀疏矩阵:

    [[2,0,1,0,0,0,0...0],
     [0,2,0,1,0,0,0...0],
     [1,0,2,0,1,0,0...0],
     [0,1,0,2,0,1,0...0],
     [0,0,1,0,2,0,1...0],
     [...]]
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scipy.sparse.dia_matrix似乎是一个很好的候选者,但是,我根本无法弄清楚如何从可用的文档中完成我想要的东西.先感谢您

seg*_*sai 6

N = 10
diag = np.zeros(N) + 2
udiag = np.zeros(N) + 1
ldiag = np.zeros(N) + 1
mat = scipy.sparse.dia_matrix(([diag, udiag, ldiag], [0, 2, -2]), shape=(N, N))
print mat.todense()
[[ 2.  0.  1.  0.  0.  0.  0.  0.  0.  0.]
[ 0.  2.  0.  1.  0.  0.  0.  0.  0.  0.]
[ 1.  0.  2.  0.  1.  0.  0.  0.  0.  0.]
[ 0.  1.  0.  2.  0.  1.  0.  0.  0.  0.]
[ 0.  0.  1.  0.  2.  0.  1.  0.  0.  0.]
[ 0.  0.  0.  1.  0.  2.  0.  1.  0.  0.]
[ 0.  0.  0.  0.  1.  0.  2.  0.  1.  0.]
[ 0.  0.  0.  0.  0.  1.  0.  2.  0.  1.]
[ 0.  0.  0.  0.  0.  0.  1.  0.  2.  0.]
[ 0.  0.  0.  0.  0.  0.  0.  1.  0.  2.]]
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  • :)它是np.zeros(N)+1的原因,因为作者可能希望在那里有一些其他值(比如100),然后代码仍然是相同的np.zeros(N) +100.但显然这是风格问题. (2认同)