我正在尝试根据我的家庭作业构建一个计算三角形区域的应用程序.不太确定我哪里出错了,但我输入了三角形的长度,并希望根据Heron的公式显示适当的区域:sqrt (s(s-a) (s-b) (s-c)).我得到的所有输出都是-0.0.这是代码:
import java.lang.Math;
public class Formula
{
double area; double s;
public double findArea(double sideA, double sideB, double sideC)
{
s = 1/2 * (sideA + sideB + sideC);
area = Math.sqrt(s*(s-sideA)*(s-sideB)*(s-sideC));
System.out.println("The area of the triangle is " + area);
return area;
}
}
Run Code Online (Sandbox Code Playgroud)
然后我有另一个主要args的文件
import java.util.Scanner;
public class findTriangleArea {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Formula triangle = new Formula();
double a,b,c;
// input triangle lengths a, b, c
Scanner inputTriangle = new Scanner(System.in);
System.out.println("Please enter triangle side a");
a = inputTriangle.nextDouble();
System.out.println("Please enter triangle side b");
b = inputTriangle.nextDouble();
System.out.println("Please enter triangle side c");
c = inputTriangle.nextDouble();
triangle.findArea(a, b, c);
}
}
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
27671 次 |
| 最近记录: |