如何:gridview里面的一个片段？

Question

我想创建一个像android市场的网格视图,我想用互联网上的数据库中的图像填充它.它需要使用androidv4.support,因为我想运行2.2直到4.0.

有人说,这不可能在4.0之前创建一个gridview,这是真的吗？

但是它只在我使用时才有效setListAdapter(),但它每行只显示一个图像,就像列表视图一样,当我改变gridview.setAdapter()它时,它再也没有工作了.

这是我的尝试:

这是ListFragment类:

 public static class ArrayListFragment extends ListFragment implements OnScrollListener{

        ImageAdapter adapter = new ImageAdapter();

        @Override
        public void onActivityCreated(Bundle savedInstanceState) {
            super.onActivityCreated(savedInstanceState);


                LayoutInflater gridInflater = (LayoutInflater) getActivity().getSystemService(Context.LAYOUT_INFLATER_SERVICE);
                View v = gridInflater.inflate(R.layout.imagelist, null);
                GridView gridView = (GridView) v.findViewById(R.id.list);




            ImageDownloader.Mode mode = ImageDownloader.Mode.CORRECT;
//            ImageAdapter imageAdapter = new ImageAdapter();
            adapter.getImageDownloader().setMode(mode);
            setListAdapter(adapter); 
//            gridView.setAdapter(adapter);
            getListView().setOnScrollListener(this);

        }

这是ImageAdapter类:

    public class ImageAdapter extends BaseAdapter {

            private Context mContext;

        private final ImageDownloader imageDownloader = new ImageDownloader();

            public static int count = 10;

private final String[] URLS = {
        "http://lh5.ggpht.com/_mrb7w4gF8Ds/TCpetKSqM1I/AAAAAAAAD2c/Qef6Gsqf12Y/s144-c/_DSC4374%20copy.jpg",
        "http://lh5.ggpht.com/_Z6tbBnE-swM/TB0CryLkiLI/AAAAAAAAVSo/n6B78hsDUz4/s144-c/_DSC3454.jpg",
        "http://lh3.ggpht.com/_GEnSvSHk4iE/TDSfmyCfn0I/AAAAAAAAF8Y/cqmhEoxbwys/s144-c/_MG_3675.jpg",
        "http://lh6.ggpht.com/_Nsxc889y6hY/TBp7jfx-cgI/AAAAAAAAHAg/Rr7jX44r2Gc/s144-c/IMGP9775a.jpg",
        "http://lh3.ggpht.com/_lLj6go_T1CQ/TCD8PW09KBI/AAAAAAAAQdc/AqmOJ7eg5ig/s144-c/Juvenile%20Gannet%20despute.jpg",
        };

            public int getCount() {
                return count;
            }

            public String getItem(int position) {
                return URLS[position];
            }

            public long getItemId(int position) {
                return URLS[position].hashCode();
            }
         public View getView(int position, View convertView, ViewGroup parent) {
                View v;

                if (convertView == null) {
                    v = LayoutInflater.from(mContext).inflate(R.layout.image_text_view,null);
                    v.setLayoutParams(new GridView.LayoutParams(200,200));

                    ImageView imageview = (ImageView)v.findViewById(R.id.image);
                    imageview.setScaleType(ImageView.ScaleType.CENTER_CROP);
                    imageview.setPadding(6, 6, 6, 6);
                    imageDownloader.download(URLS[position], imageview);
                }
             else {
                v = convertView;
            }

                return v;
            }

            public ImageDownloader getImageDownloader() {
                return imageDownloader;
            }
    }

如果有人有样品,它可能会有很大帮助.谢谢

Answer 1

这应该工作正常,你只是不能使用gridView ListFragment- 只需使用普通的旧Fragment,如果你将手动管理网格无论如何

此外,检查convertView是否为null的重点是进行视图回收 - 操作系统仅声明足够的视图来填充屏幕,而不是更多,因此如果滚动则可以重用视图而不必为新视图充气.像这样改变你的getView()以利用:

public View getView(int position, View convertView, ViewGroup parent) {
  View v;

  if (convertView == null) {
    v = LayoutInflater.from(mContext).inflate(R.layout.image_text_view,null);
    v.setLayoutParams(new GridView.LayoutParams(200,200));
  }
  else {
    v = convertView;
  }

  ImageView imageview = (ImageView)v.findViewById(R.id.image);
  imageview.setScaleType(ImageView.ScaleType.CENTER_CROP);
  imageview.setPadding(6, 6, 6, 6);
  imageDownloader.download(URLS[position], imageview);

  return v;
}

此外,getView不是BaseAdapter的功能,请尝试切换到ArrayAdapter.作为旁注,@Override当你认为你覆盖了一个基本函数时总是使用- 这样如果你犯了一个错误,编译器会给你一个错误