Wil*_*ren 12
假设您的timestamp列名为signup_date,您可以执行以下查询:
SELECT
WEEKOFYEAR(signup_date) AS weekno,
COUNT(1) AS signups
FROM your_table
GROUP BY WEEKOFYEAR(signup_date);
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这将为您提供2列的结果集,一年中的一周以及该周内有多少次注册.
编辑1:
要获得最新一周为这些结果的,你可以添加以下的查询:
SELECT
WEEKOFYEAR(signup_date) AS weekno,
COUNT(1) AS signups,
SUBDATE(signup_date, INTERVAL WEEKDAY(signup_date) DAY) AS date_of_week
FROM your_table
GROUP BY WEEKOFYEAR(signup_date);
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