TypeError:&支持的不支持的操作数类型:'float'和'float'

use*_*589 2 python syntax syntax-error

我写了这个简单的程序来计算一个人的BMI.但我无法完成它.以下是我的节目,

程序

h = input("Please Enter your height in meters:")
q = raw_input("Do you want to enter your weight in kg or lbs?")

if q=="kg":
         w1 = input("Please Enter your weight in kgs:")
         bmi1 = w1/(h*h) 
         print "Your BMI is", bmi1

         if bmi1 <= 18.5: 
                        print "Your are underweight."
         if bmi1 > 18.5 & bmi1 < 24.9: 
                                     print "Your weight is normal."
         if bmi1 > 25 & bmi1 < 29.9: 
                                   print "Your are overweight"              
         if bmi1 >= 30: 
                      print "Your are obese"                    


if q=="lbs":
          w2 = input("Please Enter your weightin lbs:")
          bmi2 = w2/((h*h)*(39.37*39.37)*703) 
          print "Your BMI is:", bmi2

          if bmi2<= 18.5: 
                        print "Your are underweight."
          if bmi2>18.5 & bmi2<24.9: 
                                  print "Your weight is normal."
          if bmi2>25 & bmi2<29.9: 
                                print "Your are overweight"         
          if bmi2>=30: 
                     print "Your are obese" 
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OUTPUT

Please Enter your height in meters:1.52
Do you want to enter your weight in kg or lbs?kg
Please Enter your weight in kgs:51
Your BMI is 22.074099723
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "bmi.py", line 11, in <module>
    if bmi1 > 18.5 & bmi1 < 24.9: 
TypeError: unsupported operand type(s) for &: 'float' and 'float'
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我哪里错了?任何人只是让我知道..

谢谢 :).

Rik*_*ggi 9

&是一个按位运算符,我认为你正在寻找布尔值and.

但请注意,Python还支持以下语法:

if 18.5 < bmi1 < 24.9:
    # ...
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既然你似乎已经缩减了缩进,那么你的脚本可能是这样的:

h = raw_input("Please enter your height in meters: ")
h = float(h)
w_unit = raw_input("Do you want to enter your weight in kg or lbs? ")
w = raw_input("Please enter your weight in {}: ".format(w_unit))
w = int(w)
if w_unit == "kg":
    bmi = w / (h*h)
elif w_unit == "lbs":
    bmi = w / ((h*h) * (39.37 * 39.37) * 703)

print "Your BMI is {:.2f}".format(bmi)
if bmi <= 18.5: 
    print "Your are underweight."
elif 18.5 < bmi <= 25: 
    print "Your weight is normal."
elif 25 < bmi < 30: 
    print "Your are overweight"              
elif bmi >= 30:
    print "Your are obese"
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有一些小的改进:

  • 显式转换(因为在Python 3中,input函数表现得像raw_input并且没有像Python 2那样input,编写输​​入可能是个好习惯)
  • 真正改变的是bmi价值,所以没有必要写两次相同的东西.

剩下要做的事情,可能是将整个脚本包装成函数:)