我有这个代码,它不适合我.它不会给出任何错误或警告.所以我不知道它有什么问题.我对结构中的指针不太熟悉,我甚至不知道代码的那一部分是否导致它不能运行.
我已经使用了Code :: Blocks和DevC++来编译它,但它们都没有任何不同.
它有点长但它只有3个功能.根本没有任何东西可以打印到屏幕上.
#include <stdio.h>
#include <stdlib.h>
struct foo{
int num;
char *word;
struct foo *ptr;
};
void func1(struct foo);
void func2(struct foo*);
void func3(struct foo);
int main() {
struct foo a;
a.num = 5;
a.word ="myword";
func1(a);
printf("1 %d %s\n", a.num, a.word);
a.num = 100;
a.word = "secondword";
func2(&a);
printf("2 %d %s\n", a.num, a.word);
a.ptr = &a;
a.num = 50;
a.word = "mylastword";
func3(a);
printf("4 %d %s\n", a.num, a.word);
}
void func1(struct foo a)
{
while(*(a.word) != '\0');
{
putchar(*(a.word));
a.word++;
}
putchar('\n');
if(a.num % 10 != 0)
{
a.num *= 2;
}
a.word--;
printf("num is %d\n", a.num);
}
void func2(struct foo *a)
{
while(*(a->word) != '\0')
{ putchar(*(a->word));
a->word++; }
putchar('\n');
if(a->num % 10 != 0)
{ a->num *= 2; }
a->word--;
printf("num is %d\n", (*a).num);
}
void func3(struct foo a)
{
if(a.num > a.ptr->num)
{ a.num = 500; }
else
{ a.num = a.ptr->num +1; }
a.word = "myotherword";
a.ptr->word = "yetAnotherWord";
printf("3 %d %s\n", a.num, a.word);
}
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任何帮助将非常感激.
谢谢你们.
void func1(struct foo a)
{
while(*(a.word) != '\0');
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在while语句后面不应该有分号.
修复后,它会打印:
[4:58pm][wlynch@watermelon /tmp] ./foo
myword
num is 10
1 5 myword
secondword
num is 100
2 100 d
3 51 myotherword
4 50 yetAnotherWord
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为了加强abelenky的评论,用调试器花了3秒才发现.
[4:59pm][wlynch@watermelon /tmp] g++ -g foo.cc -o foo
[4:59pm][wlynch@watermelon /tmp] gdb ./foo
GNU gdb 6.3.50-20050815 (Apple version gdb-1752) (Sat Jan 28 03:02:46 UTC 2012)
(gdb) run
Starting program: /private/tmp/foo
Reading symbols for shared libraries ++......................... done
^C
Program received signal SIGINT, Interrupt.
func1 (a={num = 5, word = 0x100000e91 "myword", ptr = 0x7fff5fbffa58}) at foo.cc:34
34 while(*(a.word) != '\0');
(gdb)
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