如何使用Javascript找到两个日期之间的差异

Question

我希望得到扩大日期去特定日期,所以我试图检测今天日期的特定日期.但是这里不起作用的是我的代码 如果日期是下个月27我怎么能得到剩余的日子

    var date2=new Date();
    var date1=27/5/2012;
    var diff = date1.getDate()-date2.getDate();
    var date_reaming = diff.getDate();
    document.write(date_reaming + 'days to go');

Answer 1

你的代码

date1=27/5/2012

实际上意味着27除以5除以2012.它相当于写作

date1 = 0.0026838966202783303

date1将是一个数字,这个数字没有getDate方法.

如果您将它们声明为实际日期对象

var date2 = new Date(2012, 3, 19);
var date1 = new Date(2012, 4, 27);

你将能够执行

var diff = date1 - date2;

这将为您提供两个日期之间的毫秒差异.

从这里,您可以计算如下天数:

var days = diff / 1000 / 60 / 60 / 24;

Answer 2

function getDateDiff(date1, date2, interval) {
    var second = 1000,
    minute = second * 60,
    hour = minute * 60,
    day = hour * 24,
    week = day * 7;
    date1 = new Date(date1).getTime();
    date2 = (date2 == 'now') ? new Date().getTime() : new Date(date2).getTime();
    var timediff = date2 - date1;
    if (isNaN(timediff)) return NaN;
    switch (interval) {
    case "years":
        return date2.getFullYear() - date1.getFullYear();
    case "months":
        return ((date2.getFullYear() * 12 + date2.getMonth()) - (date1.getFullYear() * 12 + date1.getMonth()));
    case "weeks":
        return Math.floor(timediff / week);
    case "days":
        return Math.floor(timediff / day);
    case "hours":
        return Math.floor(timediff / hour);
    case "minutes":
        return Math.floor(timediff / minute);
    case "seconds":
        return Math.floor(timediff / second);
    default:
        return undefined;
    }
}

console.log(getDateDiff('19/04/2012', '27/5/2012', 'days'));

Answer 3

这是答案，我从这里找到了这个 ，我的 js-fiddle 在这里

var d = new Date();
var curr_date = d.getDate();
var curr_month = d.getMonth();/* Returns the month (from 0-11) */
var curr_month_plus= curr_month+1; /* because if the month is  4 it will show output 3 so we have to add +1 with month*/ 
var curr_year = d.getFullYear();
function dstrToUTC(ds) {
    var dsarr = ds.split("/");
     var mm = parseInt(dsarr[0],10);
     var dd = parseInt(dsarr[1],10);
     var yy = parseInt(dsarr[2],10);
     return Date.UTC(yy,mm-1,dd,0,0,0); }
    function datediff(ds1,ds2) {
     var d1 = dstrToUTC(ds1);
     var d2 = dstrToUTC(ds2);
     var oneday = 86400000;
     return (d2-d1) / oneday;    }
    var a =curr_month_plus+ '/' + curr_date + '/' + curr_year;
    var b;   
    b = "5/26/2012";
    document.write(+datediff(a,b)+" day(s)<br>");