从查询中获取结果

Question

CREATE TABLE TEMP25
(
  STATUS  VARCHAR2(200 BYTE)
);

Insert into TEMP25
   (STATUS)
 Values
   ('PENDING');
Insert into TEMP25
   (STATUS)
 Values
   ('ERROR');
Insert into TEMP25
   (STATUS)
 Values
  ('ERROR');
Insert into TEMP25
   (STATUS)
 Values
   ('ERROR');
Insert into TEMP25
   (STATUS)
 Values
   ('NOT_REQUIRED');
Insert into TEMP25
   (STATUS)
 Values
   ('NOT_REQUIRED'); 
Insert into TEMP25
   (STATUS)
 Values
   ('PENDING');
Insert into TEMP25
   (STATUS)
 Values
   ('PENDING');
Insert into TEMP25
  (STATUS)
 Values
   ('ERROR');
Insert into TEMP25
   (STATUS)
Values
  ('NOT_REQUIRED');
Insert into TEMP25
  (STATUS)
 Values
  ('ERROR');
Insert into TEMP25
   (STATUS)
 Values
  ('INVALID');
Insert into TEMP25
   (STATUS) 
 Values
   ('INVALID');
Insert into TEMP25
  (STATUS)
 Values
  ('PENDING');

我想写一个查询,以便我得到计数

TOTAL_RECORDS  TOTAL_PENDING TOTAL_NOT_REQUIRED   TOTAL_PENDING
-----------------------------------------------------------------
   14               4             3                   5 
-----------------------------------------------------------------

我想按顺序和一个查询中的记录,我已尝试使用with table它的子句...是否有任何其他解决方案...并且dnt想要无效的记录

Answer 1

您可以使用SUM/CASE或(SUM/DECODE如果您愿意)

Select
   COUNT(*) TOTAL_RECORDS  ,
   SUM(case when status = 'PENDING' then 1 else 0 END) TOTAL_PENDING, 
   SUM(case when status = 'NOT_REQUIRED' then 1 else 0 END) TOTAL_NOT_REQUIRED, 
   SUM(case when status = 'ERROR' then 1 else 0 END) TOTAL_ERROR


FROM temp25

看到它在这里工作

你也可以使用数据透视,但获得计数(*)有点难看

WITH 
COUNTS AS(
select * 
from (
   select status
   from TEMP25 t
)
pivot 
(
   count(status)
   for status in ('PENDING' AS TOTAL_PENDING,
                  'NOT_REQUIRED' AS TOTAL_NOT_REQUIRED,
                  'ERROR' AS TOTAL_ERROR)
))


SELECT COUNT(*) total_records, 
       total_pending, 
       total_not_required, 
       total_error 
FROM   temp25, 
       counts 
GROUP  BY total_pending, 
          total_not_required, 
          total_error 

透视版