从表单绑定play framework 2.0中的多个对象

Question

我拼命地尝试从表单提交中接收值列表并将其绑定到对象列表.

什么有效是检索单行:

//class
case class Task(name: String, description: String)

val taskForm: Form[Task] = Form(
  mapping(
  "name" -> text,
  "description" -> text

  )(Task.apply)(Task.unapply)
)


//form
<tr>
  <td><input name="name" type="text" class="span2" placeholder="Name..."></td>
  <td><textarea name="description" class="autoexpand span7" rows="1"     placeholder="Description..."></textarea>
  </td>
</tr>

//receiving action:
val task = taskForm.bindFromRequest.get

但是现在我想提交多个类型为task的对象,例如:

<tr>
  <td><input name="name[0]" type="text" class="span2" placeholder="Name..."></td>
  <td><textarea name="description[0]" class="autoexpand span7" rows="1" placeholder="Description..."></textarea></td>                   
</tr>
<tr>
  <td><input name="name[1]" type="text" class="span2" placeholder="Name..."></td>
  <td><textarea name="description[1]" class="autoexpand span7" rows="1" placeholder="Description..."></textarea></td>                   
</tr> 

现在执行taskForm.bindFromRequest.get失败.

有人想出一个解决方案吗？或者你处理这种情况完全不同？

Answer 1

好吧,谢谢你暗示我再看一下这些文档,我已经看过它们了,但是从来没有能够把它结合起来让它起作用.我想这是因为我是一个scala noob.但是,我再给它一段时间后才开始工作,这是我的解决方案:

//classes
case class Task(name: String, description: String)
case class Tasks(tasks: List[Task])

val taskForm: Form[Tasks] = Form(
  mapping(
  "tasks" -> list(mapping(
    "name" -> text,
    "description" -> text
  )(Task.apply)(Task.unapply))
)(Tasks.apply)(Tasks.unapply)
)

//form
<tr>
  <td><input name="tasks[0].name" type="text" class="span2" placeholder="Name..."></td>
  <td><textarea name="tasks[0].description" class="autoexpand span7" rows="1" placeholder="Description..."></textarea></td>                   
</tr>
<tr>
  <td><input name="tasks[1].name" type="text" class="span2" placeholder="Name..."></td>
  <td><textarea name="tasks[1].description" class="autoexpand span7" rows="1" placeholder="Description..."></textarea></td>                   
</tr>

最后做一个:

val tasks = taskForm.bindFromRequest.get

检索任务列表.