scr*_*ddy 4 python loops tkinter
我希望代码在后台运行并定期更新我的GUI.我怎么能做到这一点?
例如,假设我想在GUI代码的后台执行类似的操作,您可以在下面看到:
x = 0
while True:
print(x)
x = x + 1
time.sleep(1)
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这是GUI代码:
class GUIFramework(Frame):
def __init__(self,master=None):
Frame.__init__(self,master)
self.master.title("Volume Monitor")
self.grid(padx=10, pady=10,sticky=N+S+E+W)
self.CreateWidgets()
def CreateWidgets(self):
textOne = Entry(self, width=2)
textOne.grid(row=1, column=0)
listbox = Listbox(self,relief=SUNKEN)
listbox.grid(row=5,rowspan=2,column=0,columnspan=4,sticky=N+W+S+E,pady=5)
listbox.insert(END,"This is an alert message.")
if __name__ == "__main__":
guiFrame = GUIFramework()
guiFrame.mainloop()
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有点不清楚你的顶部代码应该做什么,但是,如果你只想每秒调用一个函数(或你想要的每一秒),你可以使用该after方法.
所以,如果你只是想做点什么textOne,你可能会做以下事情:
...
textOne = Entry(self, width=2)
textOne.x = 0
def increment_textOne():
textOne.x += 1
# register "increment_textOne" to be called every 1 sec
self.after(1000, increment_textOne)
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您可以将此函数作为您的类的方法(在本例中我称之为callback),您的代码将如下所示:
class Foo(Frame):
def __init__(self, master=None):
Frame.__init__(self, master)
self.x = 0
self.id = self.after(1000, self.callback)
def callback(self):
self.x += 1
print(self.x)
#You can cancel the call by doing "self.after_cancel(self.id)"
self.id = self.after(1000, self.callback)
gui = Foo()
gui.mainloop()
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