如何在WebView中获取POST请求的JSON响应？

Question

我有一个WebView包含表格的html(帖子).单击某个提交按钮时,我会收到JSON响应.

我怎样才能获得这个JSON？

如果我不拦截请求,json会显示在webview上,所以我想我应该使用shouldInterceptRequest(我使用的是API 12),但我不知道如何获取json.

或者也许有更好的方法,比如拦截响应而不是请求？

mWebView.loadUrl(myURL);  

isPageLoaded = false; // used because the url is the same for the response

mWebView.setWebViewClient(new WebViewClient() {
    @Override
    public WebResourceResponse shouldInterceptRequest (WebView view, String url) {

        if(isPageLoaded){
            // get the json
            return null;
        }
        else return super.shouldInterceptRequest(view, url);
    }

    public void onPageFinished(WebView view, String url) {
        isPageLoaded = true;
    }
});

谢谢

Answer 1

以下是我如何实现这一点,因为提到的方法开始抱怨UI线程网络连接.

使用ChromeWebView客户端和控制台记录输出

    public void OnSignUp_Click(View v) {
    WebView mWebview = new WebView(this);

    mWebview.getSettings().setJavaScriptEnabled(true); // enable javascript

    final Activity activity = this;

    mWebview.setWebChromeClient(new WebChromeClient() {
        public boolean onConsoleMessage(ConsoleMessage cmsg)
        {

                /* process JSON */
            cmsg.message();
            return true;

        }
    });

    mWebview.setWebViewClient(new WebViewClient() {

        public void onReceivedError(WebView view, int errorCode,
                String description, String failingUrl) {
            Log.e("Load Signup page", description);
            Toast.makeText(
                    activity,
                    "Problem loading. Make sure internet connection is available.",
                    Toast.LENGTH_SHORT).show();
        }

        @Override
        public void onPageFinished(WebView view, String url) {
            view.loadUrl("javascript:console.log(document.body.getElementsByTagName('pre')[0].innerHTML);");
        }
    });

    mWebview.loadUrl("https://yourapp.com/json");

}

希望它能帮助别人.

Answer 2

你应该覆盖的shouldOverrideUrlLoading方法WebViewClient

@Override
public boolean shouldOverrideUrlLoading (WebView view, String url) {

    if(flag) { 

            URL aURL = new URL(url); 
            URLConnection conn = aURL.openConnection(); 
            conn.connect(); 
            InputStream is = conn.getInputStream(); 
            // read inputstream to get the json..
            ...
            ...
            return true;
    }

    return false
}

@override
public void onPageFinished (WebView view, String url) {
    if (url contains "form.html") {
        flag = true;
    }
}

另请参阅此处如何从WebView获取网页内容？