我正在使用JAXB解析xml。我有一个如下所示的架构,并且在此架构上定义了两个xml文件a.xml和b.xml。a.xml通过xi:include xml标记对b.xml进行依赖。请提交以下示例以获取更清晰的数据
I have followng schema definition:
<?xml version="1.0" encoding="UTF-8"?>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" elementFormDefault="qualified" attributeFormDefault="unqualified">
<xs:element name="Task">
<xs:complexType>
<xs:sequence>
<xs:element ref="Details" minOccurs="1" maxOccurs="unbounded"/>
</xs:sequence>
</xs:complexType>
</xs:element>
<xs:element name="Details">
<xs:complexType>
<xs:sequence>
<xs:element name="NAme" type="xs:string"/>
</xs:sequence>
</xs:complexType>
</xs:element>
</xs:schema>
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这是两个xml文件:
a.xml:
<?xml version="1.0" encoding="UTF-8"?>
<Task xmlns:xi="http://www.w3.org/2001/XInclude">
<Details>
<xi:include href="b.xml"/>
</Details>
</Task>
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b.xml:
<?xml version="1.0" encoding="UTF-8"?>
<Detail>
<Name>Name1</Name>
</Detail>
<Detail>
<Name>Name2</Name>
</Detail>
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现在,我使用JAXB SAXFactory将其解析为:
JAXBContext jaxbcon = JAXBContext.newInstance("schema-definition-jaxb-files");
unmar = jaxbcon.createUnmarshaller();
SAXParserFactory spf = SAXParserFactory.newInstance();
spf.setXIncludeAware(true);
XMLReader xr = spf.newSAXParser().getXMLReader();
SAXSource source = new SAXSource(xr, new InputSource(new FileInputStream(xmlfilename)));
Object obj = unmar.unmarshal(source);
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解析成功,但是Details JAXB标记对象为null。无论如何,a.xml文件中的xi:include标记不会变平。任何的想法?
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